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3 years ago

5

Represent the proportional relationship described with an equation where p equals pepperoni and z equals pizza: eighteen peppero

ni for each pizza A) p = 18z B) 18p = z C) p = 18 z D) z = 18 p

1 answer:

viktelen [127]3 years ago

3 0

Answer:

The answer is A. p=18z I just took the test

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What is the completely factored form of x^4y- 4xły - 5y?

tamaranim1 [39]

If you mean by completely factored form of x^4y - 4x2y - 5y

Then the answer is y (x^2 - 5) (x^2 + 1)

3 0

3 years ago

For circle C, CG = CE, CG is perpendicular to FB, and CE is perpendicular to DA. What conclusion can be made? a circle with cent

svetlana [45]

Answer:

A circle with center C has chords FB and DA which are equidistant from C.

Step-by-step explanation:

A chord is a straight line drawn from a point on the circumference of a circle to another point on the circumference, without passing through the center of the circle.

From the given question, a circle center C has two chords FB and DA that are equidistant from the center of the circle. The distant of FB from C is CG and the distance of DA from C is CE. But CG = CE, which implies that the two chords have equal distant from the center of the circle.

Therefore line CG from center C intersects FB at G, and line CE from center C intersects DA at E.

8 0

3 years ago

Solve the simultaneous equations<br> y = 9 - X<br> y = 2x2 + 4x + 6

kenny6666 [7]

Answer:

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

Step-by-step explanation:

Given the simultaneous equations

$y=9-x$

$y\:=\:2x^2\:+\:4x\:+\:6$

Subtract the equations

$y=9-x$

$-$

$\underline{y=2x^2+4x+6}$

$y-y=9-x-\left(2x^2+4x+6\right)$

$\mathrm{Refine}$

$x\left(2x+5\right)=3$

$\mathrm{Solve\:}\:x\left(2x+5\right)=3$

$2x^2+5x=3$ ∵ $\mathrm{Expand\:}x\left(2x+5\right):\quad 2x^2+5x$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$2x^2+5x-3=3-3$

$\mathrm{Solve\:with\:the\:quadratic\:formula}$

$\mathrm{Quadratic\:Equation\:Formula:}$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=5,\:c=-3:\quad x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}v\\$

$x=\frac{-5+\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$=\frac{-5+\sqrt{5^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{4}$

$=\frac{-5+7}{4}$

$=\frac{2}{4}$

$=\frac{1}{2}$

Similarly,

$x=\frac{-5-\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}:\quad -3$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{1}{2},\:x=-3$

$\mathrm{Plug\:the\:solutions\:}x=\frac{1}{2},\:x=-3\mathrm{\:into\:}y=9-x$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}\frac{1}{2}:\quad y=\frac{17}{2}$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}-3:\quad y=12$

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

3 0

4 years ago

An owner of a kid's store purchased 150 shirts for a total of $32,500. If they wish to sell them for at least $66,000, how much

kozerog [31]

If they want $66,000 for 150 shirts then they need to sell them for $440.
$66,000 ÷ 150 = $440. (Expensive kids shirts)

5 0

3 years ago

Which best describes the equation that the graph represents?

andreev551 [17]

Answer:

y= $\frac{9}{5}$ x

Step-by-step explanation:

Given the two points:

Origin (x1, y1) = (0, 0)
The point (x2, y2) = (5, 9)

Because the x-axis is labeled time (in minutes) and the y-axis is labeled distance (in kilometers).

=>Time, x the independent variable,and distance is the dependent variable.

We have the standard form of a linear equation is:

y= mx + b where a is the slope

We know that, the slope of the function is:

m = $\frac{y2-y1}{x2-x1}$

In this situatuon, m = $\frac{9-0}{5-0} = \frac{9}{5}$

=> y= $\frac{9}{5}$ x + b(1)

The line that goes through (0, 0) so we substitute (0, 0) into (1), we have:

0 = $\frac{9}{5}$ *0 + b

<=> b = 0

So our equation that the graph represents is: y= $\frac{9}{5}$ x

8 0

3 years ago

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