If it's 4|6-8|, the answer would be 8
6-8=-2 but since its absolute value it would just be 2
4×2=8
Y=2x + 5, the Y-intercept is 5
Answer:
y=-4x^2+9x+9
Step-by-step explanation:
1st: we assume the equation will be in standard form (ax^2+bx+c)
2nd: since the graph passes through (0,9) then the y-intercept is @(0,9) or your c is 9.
3rd: since it passes through (2,11) then 11=4a+2b+c
4th: since it also passes through (3,0) then 0=9a+3b+c
* so we have c=9, 11= 4a+2b+c, and 0= 9a+3b+c*
So a=-4, b=9, c=9
plug in the numbers and you get y= 4x^2+9x+9
Hope this helps you. :3
hi
It's a kind of multiplication where you do a serie of multiplication starting from your number until one. It written with a "!" after the number.
ex : 3! = 3*2*1 = 6
10! = 10*9*8*7**6*5*4*3*2*1 = 2628800
I started at (-2, 0) but you can start at any point on the graph that goes through the corner of the square (if that makes sense) like a point on the graph. From one point to the next, you go down one and one to the right, therefore the slope is a -1