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The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as
A=3 √(4) units ^2
<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>Generally, the equation for is mathematically given as
The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:
The partial derivatives of a function are f x and f y.
When these numbers are plugged into equation (1) and the integrals are given bounds, we get:
In conclusion, the area is
A=3 √4 units ^2
Read more about the plane
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Answer:
y = -x + 4
Step-by-step explanation:
The point-slope formula for a straight line is
y – y₁ = m(x – x₁)
x₁ = -1; y₁ = 5; m = -1 Substitute the values
y – 5 = -1(x + 1) Remove parentheses
y – 5 = -x - 1 Add 5 to each side
y = -x + 4
The graph is a straight line with a y-intercept at y = +4 and a slope = -10/10
= -1.
