Answer:
2, sqrt of 7633
Step-by-step explanation:
for now, we'll leave the 3rd side as x
y using the Pythagorean theorem, we can conclude that (1) 48^2+x^2=73^2 or (2) 48^2+73^2=x^2.
1. If we conclude the x isn't the longest, the x would be 3025 which is the sqrt of 55, now is invalid because the 2 smallest sides can't be more than the longest side when they add up 55+48>73 so that is invalid
2. Then, it leaves us with only 1 choice left! concluding that the 3rd side is the longest. Which the answer is sqrt of 7633
Q. How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
Solution:
Here we are given with the sides of the triangle as 5m, 16m and 5.
As the Triangle inequality we know that
The sum of the length of the two sides should be greater than the length of the third side. But this inequality fails here.
Hence no triangle can be made.
So the correct option is None.
Q.How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?
Solution:
Here we are given with the sides of the triangle as 6m, 2m and 7m.
As the Triangle inequality we know that
The sum of the length of the two sides should be greater than the length of the third side. The given values follows the triangle inequality.
Hence one triangle can be formed.
So the correct option is one.
10+8/2-4
PEMDAS
parenthasese
exxonents
multiplication or division
addiotn or subtration next
10+8/2-4
8/2 first
4
10+4-4
add
10+4=14
minus
14-4=10
answer is 10
Answer:
3 inches
Step-by-step explanation:
Lenght = 18 inches
Width =15 inches
Perimeter of the rectangular painting and frame = 90 inches
Let X be the width of the frame
The width of the framed picture = 15 + 2x
The length of the framed picture = 18 + 2x
Perimeter = 2 (L + W)
90 = 2(15 + 2x + 18+ 2x)
90 = 2(33 + 4x)
90 = 66 + 8x
8x = 90 - 66
8x = 24
x = 24/8
x = 3 inches
the width of the frame is 3 inches
Answer:
y = (x + 4)(x - 9)
Step-by-step explanation:
x = {-4, 9}
y = (x + 4)(x - 9)
