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3 years ago

Write if the following statement is true or false. Equivalent decimals are decimals that have the same value.

Mathematics

2 answers:

viktelen [127]3 years ago

7 0

True it is always same value

Alexxandr [17]3 years ago

4 0

That is true. It doesn't matter how many 0s you put after it just before it.

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HELP PLEASE! 15 POINTS

Goshia [24]

Answer:

Its 58

Step-by-step explanation:

2+2+2+2+2+4+4+4+6+10+10=58 but the closest number to it is 56

8 0

2 years ago

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Consider a circle that has a circumference of 28/3.14 centimeters. What is the area of this circle? Answer fast plz also can you

bija089 [108]

Answer:

$A=6.33\ cm^2$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

$C=2\pi r$

we have

$C=\frac{28}{3.14}\ cm$

$\pi=3.14$

substitute the values

$\frac{28}{3.14}=2(3.14)r$

$r=\frac{28}{19.7192}\ cm$

$r=1.42\ cm$

step 2

Find the area of the circle

The area of the circle is equal to

$A=\pi r^{2}$

substitute the values

$A=(3.14)(1.42)^{2}$

$A=6.33\ cm^2$

7 0

3 years ago

What is the sum of the angle measures in this shape

Alexxx [7]

Answer:

180°

Step-by-step explanation:

The sum of angles in any triangle is 180°

3 0

3 years ago

60 points answer asap

kow [346]

The point slope form of a line is written as y - y1 = m(x -x1)

Where m is the slope and x1 and y1 are the points on the line.

You are told the slope is 3 and the point is (2,-1/2)

x1 is 2 and y1 is -1/2

Replace those in the equation to get:

y- (-1/2) = 3(x-2)

Simplify to get the final answer:

y + 1/2 = 3(x-2)

4 0

3 years ago

Read 2 more answers

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m

Harrizon [31]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

Let $\mu$ = average mg of mercury in compact fluorescent bulbs.

So, Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean mg of mercury = 3.59

$\sigma$ = population standard deviation = 0.18 mg

n = sample of bulbs = 25

So, test statistics = $\frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }$

= 2.50

The value of z test statistics is 2.50.

Now, P-value of the test statistics is given by;

P-value = P(Z > 2.50) = 1 - P(Z $\leq$ 2.50)

= 1 - 0.9938 = 0.0062

Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0

3 years ago