Given:
Vector v have an initial point at (7, -6) and a terminal point at (1, -4).
To find:
The components of vector v.
Solution:
It initial point of a vector is
and terminal point is
, then the vector is
![\mathbf{v}=\left](https://tex.z-dn.net/?f=%5Cmathbf%7Bv%7D%3D%5Cleft%3Cx_2-x_1%2Cy_2-y_1%5Cright%3E)
Vector v have an initial point at (7, -6) and a terminal point at (1, -4). so, vector v is defined as
![\mathbf{v}=\left](https://tex.z-dn.net/?f=%5Cmathbf%7Bv%7D%3D%5Cleft%3C1-7%2C-4-%28-6%29%5Cright%3E)
![\mathbf{v}=\left](https://tex.z-dn.net/?f=%5Cmathbf%7Bv%7D%3D%5Cleft%3C-6%2C-4%2B6%5Cright%3E)
![\mathbf{v}=\left](https://tex.z-dn.net/?f=%5Cmathbf%7Bv%7D%3D%5Cleft%3C-6%2C2%5Cright%3E)
Therefore, vector is
and its x and y components are -6 and 2 respectively.
The x is the 4 and the y is the 3 (4,3)
Answer:
y=2
-7x-4
three linear equations
c=-4 ;4a+b=1 ; 9=a-b
Step-by-step explanation:
Simply assume a standard parabola equation y=a
+bx +c
(here a, b, c are three independent variables)
Three coordinates as shown in graph are (0,4), (4,0) ,(-1,5)
Now put these points in the equation of parabola and get three linear equations.
[1] c=-4
[2] 4a+b=1
[3] 9=a-b
Now substitute value of a from equation 2 into 3 in terms of b
a= ![\frac{1-b}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1-b%7D%7B4%7D)
9=
-b
b=-7
a=2
y=2
-7x-4
Answer:
The value of z is:
z = 6
Step-by-step explanation:
We have been given 4 options of z. Lets substitute each value in the given equation to see which option satisfies.
<h3 /><h3>For z = 3</h3>
sin(9z - 1) = cos(6z + 1)
sin(9(3) - 1) = cos(6(3) + 1)
sin(26) = cos(19)
0.438 = 0.945
FALSE
<h3 /><h3>For z = 4</h3>
sin(9z - 1) = cos(6z + 1)
sin(9(4) - 1) = cos(6(4) + 1)
sin(35) = cos(25)
0.574 = 0.965
FALSE
<h3 /><h3>For z = 5</h3>
sin(9z - 1) = cos(6z + 1)
sin(9(5) - 1) = cos(6(5) + 1)
sin(44) = cos(31)
0.695 = 0.857
FALSE
<h3 /><h3>For z = 6</h3>
sin(9z - 1) = cos(6z + 1)
sin(9(6) - 1) = cos(6(6) + 1)
sin(53) = cos(37)
0.799 = 0.799
TRUE
<h3 />