The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.
If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.
The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.
The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ = coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.
This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force to overcome the centripetal force.
Answer:
b = -2
Step-by-step explanation:
Start with your given:
-3b + 7 = 13
Subtract 7 on both sides:
-3b = 6
Then, divide -3 on both sides and solve:
b = -2
Answer:
0.708
Step-by-step explanation:
A great way to solve for probability is to create a fraction.
In our case, we can see that 17 out of 24 times they made it.
17/24 is our fraction.
Since the viniculum in a fraction represents division, we really have 17 divided by 24.
That is 0.7083.....
Rounding gives 0.708 as our final answer.
If you need me to clarify anything i got you
