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iogann1982 [59]
3 years ago
14

What is 5 7/8 as an improper fraction?

Mathematics
2 answers:
padilas [110]3 years ago
8 0

Answer: 47/8

Step-by-step explanation:

5 x 8= 40

40 + 7= 47

And u still have the denominator.

Virty [35]3 years ago
6 0

Answer:

47/8

Step-by-step explanation:

8×5=40

40+7=47/8

ans47/8

pliz mark my answer brainliest

good luck

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Divide 180 degrees by the ratio 4:5:9, Help Please
mixas84 [53]
Add all the numbers in the ratio together to get 18 then divide 180 by 18 to equal 10. then times that by each individual number in the ratio. so the  answer is 40:50:90
7 0
3 years ago
Ricardo spends 8/9 hr. reading the paper. He spends 1/4 of the time reading world news and splits the remaining time equally bet
lapo4ka [179]
Total time spent reading is = 8/9 hour

He spends 1/4 of the time reading world news. That is =  1/4 * 8/9 =  2/9 hour

Splits the remaining time equally.  Remaining time =  8/9 - 2/9 =  6/9

Splitting it equally =  6/9  divided by 2 =  6/9  * 1/2 =  3/9  = 1/3

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I hope this helps.
5 0
3 years ago
What is the value of -9 + (-4 + 7) (2)?
RUDIKE [14]

Answer:

try -3

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
If the weight of 7 sheets of paper is 35 grams, find how many sheets of paper it will take to weigh 1.5 kg
Leokris [45]

Answer:

300 sheets

Step-by-step explanation:

if you divide 35 by 7, you get 5

then divide 1,500 by 5 to get 300.

3 0
3 years ago
A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.
IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car (v_0) = 40 ft/sec

Deceleration of the car (\frac{dv}{dt}) = -10 ft/sec²

Final speed of the car (v_x) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, \frac{dv}{dt}=-10\ ft/sec^2

Negative sign means the velocity is decreasing with time.

Now, \frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt}) using chain rule of differentiation. Therefore,

\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft

Therefore, the car travels a distance of 80 feet before stopping.

4 0
3 years ago
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