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PtichkaEL [24]
2 years ago
12

The mean of 12 numbers is 20 and the mean of another 8 numbers is 25 find the mean of the 20 numbers

Mathematics
1 answer:
AysviL [449]2 years ago
8 0

Answer:

22

Step-by-step explanation:

mean is calculated as

mean = \frac{sum}{count}

Given the mean of 12 numbers is 20 , then

\frac{sum}{12} = 20 ( multiply both sides by 12 )

sum = 240

Given the mean of 8 numbers is 25 , then

\frac{sum}{8} = 25 ( multiply both sides by 8 )

sum = 200

Total sum of the 20 numbers = 240 + 200 = 440, then mean of 20 numbers is

mean = \frac{440}{20} = 22

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Step-by-step explanation:

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3 years ago
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If the angle NME = x+97, the angle EML = x+66, and the angle NML = 141, find the angle EML
defon

Answer:

∠ EML = 94°

Step-by-step explanation:

See the attached diagram.

The three angles ∠ NME, ∠ EML and ∠ NML together make 360°.

Now, ∠ NME = x + 97, ∠ EML = x + 66 and ∠ NML = 141°

Hence, (x + 97) + ( x + 66) + 141 = 360

⇒ 2x + 304 = 360

⇒ 2x = 56

⇒ x = 28

So, ∠ EML = x + 66 = 28 + 66 = 94° (Answer)

6 0
3 years ago
Which of the following integrals cannot be evaluated using simple substitution?
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the second and the last,

since quadratic inside radical without multiplication with linear function

8 0
3 years ago
Find the solution of the system 2x-y=0 and 4x-2=2
yanalaym [24]

Answer:

(1, 2)

Step-by-step explanation:

2x-y=0

4x-2=2

-----------

y=2x-0

y=2x

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4x=2+2=4

4x=4

x=4/4=1

---------------

y=2(1)=2

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8 0
3 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11)
Katen [24]

Answer:

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).

Step-by-step explanation:

We have given the vertices at (0, ±9) and foci at (0, ±11).

Let (0,±a)  = (0,±9) and (0,±c)  = (0,±11)

The standard equation of parabola is:

\frac{y^{2} }{a^{2} } -\frac{x^{2} }{b^{2} }=1

From statement, a  = 9

c² = a²+b²

(11)²  = (9)²+b²

121-81  = b²

40  = b²

Putting the value of a² and b² in standard equation of parabola, we have

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 which is the answer.

3 0
3 years ago
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