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tino4ka555 [31]
3 years ago
12

okay. i need help i been working on this for like- 4 hours i dont know chile anyways so. im kinda not- smart- right now and i lo

st my brain. so a little help please <3

Mathematics
1 answer:
Fed [463]3 years ago
8 0

1. 8.2 repeating

2. 0.878

3. 22.02 repeating

4. 1.852 repeating

5. 0.76335877

6. 0.270 repeating

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FrozenT [24]
U believe the answer is no, I believe this because eight 9 oz. bags is 72 oubces and both of them make less than that in 10 minutes. Machine A would make 42.5 oz in 10 minutes and Machine B would make 45 oz in 10 minutes.
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4 years ago
I NEED HELP PLEASE!!!
meriva

Answer:

a

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

8 0
3 years ago
What is in between 0.8 and 0.9
Fantom [35]
0.85 is between 0.8 and 0.9
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What system of equations represents the graph
Elodia [21]

Answer:

The answer is C because the two figures are not congruent.

4 0
4 years ago
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