F(x) = x^2 - 6x + 4 {-3, 0, 5} (x, y) x is the domain, y is the range.
plug in the domain numbers into the equation to find the range.
y = x^2 - 6x + 4
y = -3^2 - 6(-3) + 4
y = 9 - (-18) + 4
y = 9 + 18 + 4
y = 31 (-3, 31)
y = x^2 - 6x + 4
y = 0^2 - 6(0) + 4
y = 0 - 0 + 4
y = 4 (0, 4)
y = x^2 - 6x + 4
y = 5^2 - 6(5) + 4
y = 25 - 30 + 4
y = -1 (5, -1)
c. {-1, 4, 31}
hope this helped, God bless!
HI THERE!!!
The answer you chose is correct: Face
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~TRUE BOSS
Answer:
(x+5)^2+(y-12)^2=256
Step-by-step explanation:
Comparing the given (x+5)^2+(y-12)^2=256
to (x - h)^2 + (y - k)^2 = r^2,
we see that h must be -5, k must be 12 and r must be 16. This is the desired equation of the circle with center at (-5, 12) and radius 16.
Answer:
θ =
Step-by-step explanation:
Since the vertical height of the mountain is 800 feet, and the distance from the top to its base is 1600 feet. Let the angle of elevation be represented by θ, applying the required trigonometric function;
Sin θ =
Sin θ =
= 0.5
θ = 0.5
θ =
Thus, the angle of elevation from the base to the top of the mountain is .
Area= l×w
= 8/9 × 2/3
=16/27
area = 16/27 m²
hope i hel[ped