Find the x-intercept of parabola with vertex (1,-17) and y-intercept (0,16)?

1 answer:

5 0

Y=a(x-1)^2 -17 is the equation of the parabola.
at (0,16), 16=a(0-1)^2 -17. Solve for a = 33.
Equation is then y=33(x-1)^2-17 so when y=0,
(x-1)^2 = 17/33
x-1 = + and - square root of 17/33
x = 1.7177 and 0,2823 as the intercepts

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