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Vlada [557]
4 years ago
8

Find the x-intercept of parabola with vertex (1,-17) and y-intercept (0,16)?

Mathematics
1 answer:
Ad libitum [116K]4 years ago
5 0
Y=a(x-1)^2 -17 is the equation of the parabola.
at (0,16), 16=a(0-1)^2 -17.  Solve for a = 33.
Equation is then y=33(x-1)^2-17 so when y=0,
(x-1)^2 = 17/33
x-1 = + and - square root of 17/33
x = 1.7177 and 0,2823 as the intercepts
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Pam runs 50 meters in 12 seconds, how far can she run in 7 seconds?
podryga [215]

Answer: 30 meters

Step-by-step explanation:

50/12=4.1666

4.1666x7=29.162 round it to 30

5 0
3 years ago
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What's the solution to 3x – 6 < 3x + 13? A. x > 5 B. There are no solutions. C. There are infinitely many solutions. D. x
erma4kov [3.2K]

Answer:

C. There are infinitely many solutions.  

Step-by-step explanation:

3x – 6 < 3x + 13

Subtract 3x from each side

-6 < -13

This inequality is always true.

There are infinitely many solutions.

8 0
3 years ago
Jamie has $37 and he's a bank account on Sunday the table shows his account activity for the next 4 days what was the balance in
wolverine [178]

Answer:

You divide 37 and 4 then the answer is 8 remainder 5

Step-by-step explanation:


3 0
3 years ago
Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29
hram777 [196]

Answer:

\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }

Step-by-step explanation:

Hello,

I assume that we are working in \mathbb{C}, otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

   p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

So

\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }

Now, we need to find the zeroes of the second factor, meaning finding x so that:

x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4}  \\ \\  x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\  x = 2+5i \ \text{ or } \ x = 2-5i

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
One year Terry had the lowest ERA​ (earned-run average, mean number of runs yielded per nine innings​ pitched) of any male pitch
Colt1911 [192]

Answer:

Their respective​ z-scores are:

Thomas : -2.15279

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Which player had the better year relative to their​ peers, Terry or Karla ​? ​

Terry had a better year because he had a lower Era and he was a better pitcher.

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ,

where x is the raw score,

μ is the population mean

σ is the population standard deviation.

any male pitcher at his​ school,

For Thomas:

z = (x-μ)/σ

x = 2.85 μ = 4.893 σ = 0.949.

z = 2.85 - 4.893/0.949

z = -2.15279

For Karla

z = (x-μ)/σ

x = 2.95 μ = 4.348 σ = 0.997.

z = (2.95 - 4.348) /0

z = -1.40221

Their respective​ z-scores are:

Thomas : -2.15279

Karla : -1.40221

Which player had the better year relative to their​ peers, Terry or Karla ​? ​(Note: In​ general, the lower the​ ERA, the better the​ pitcher.)

Terry had a better year because he had a lower Era and he was a better pitcher.

5 0
3 years ago
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