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11Alexandr11 [23.1K]

3 years ago

10

Can someone help me with this question?

1 answer:

charle [14.2K]3 years ago

6 0

Finding the sol'n to f(x) - g(x) = 0 is the same as finding the solution of f(x)=g(x). You could do this analytically by setting the actual function f(x) = g(x) and solving for x (and then for y), or you could estimate the solution from the given graph. The two lines intersect at approx. x=-3.75, y=2.5.

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Convert to standard form.<br> y-5=-3(x+2)

Paul [167]

Answer:

Step-by-step explanation:

y-5=3(x+2)

y-5=3x+6

y-5-6=3x+6-6

y-1=3x

7 0

3 years ago

Susan made 75 pieces of peanut brittle to share equally with her friends. She put 4 pieces of peanut brittle in each bag. She ga

BabaBlast [244]

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72/4=18 with remainder of 3 peices given to her mom

Step-by-step explanation:

6 0

2 years ago

Marcie baked several pies. She used 4 cups of flour for the dough. How many pints of flour did she use?

Tcecarenko [31]

Answer:

well if several means 3 then she used 12 pints.

Step-by-step explanation:

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3 0

2 years ago

If a runner runs at a constant rate of 6 miles per hour how much time would it take for her to run 9 miles

Neko [114]

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1 1/2

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5 0

2 years ago

Read 2 more answers

Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. Assume that the cost o

Snezhnost [94]

Answer:265.25

Step-by-step explanation:

Given

Volume of box $=12 m^3$

height is 3 times the width

let height, length and breadth be H, L & B

$H=3\times B$

$V=12=L\times B\times H$

4=B^2\times L[/tex]

$L=\frac{4}{B^2}$

Cost of side walls $ $8/m^2$

Cost of base $ $12/m^2$

Cost of side walls $=(2LH+2BH)\cdot 8$

Cost of base $=12LB$

Total cost $C=16LH+16BH+12LB$

$C=48LB+48B^2+12LB$

$C=\frac{192}{B}+48B^2+\frac{48}{B}$

differentiate C w.r.t B to get minimum cost

$\frac{\mathrm{d} C}{\mathrm{d} B}=-\frac{192}{B^2}+2\times 48 B-\frac{48}{B^2}$

$B^3=\frac{240}{2\times 48}$

$B=1.35 m$

$H=3\times 1.35=4.07 m$

L=2.19 m

C=$ 265.25

3 0

2 years ago