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3 years ago

Mjnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn

Mathematics

1 answer:

Radda [10]3 years ago

7 0

I don't know what this is supposed to mean, but thanks for the free points! ;)

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Solve the right triangle.<br> Round your answers to the nearest tenth.

katen-ka-za [31]

Answer: A= 42 degrees

Step-by-step explanation:

A= 180-90-48=42 (degrees)

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2 years ago

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Given:

djverab [1.8K]

Answer:

The CONVERSE of p → q is q → p will be written as

i.e If 3x -4 = 20, then 2x = 16.

Step-by-step explanation:

Given:

p: 2x = 16

(one statement)

q: 3x – 4 = 20

(another statement)

The given statement is p → q can be written as

i.e IF 2x = 16, then 3x – 4 = 20

The CONVERSE of p → q is q → p will be written as

i.e If 3x -4 = 20, then 2x = 16.

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3 years ago

Write each expression in simplified radical form PLEASE HELP ITS DUE FRIDAY AND I DONT UNDERSTAND THIS AT ALL REALLY BAD TEACHER

Nonamiya [84]

Answer:

1) The simplified radical form is $\sqrt{36x^2}=6x$

2) The simplified radical form is $\sqrt{72x^3}=6x\sqrt{2x}$

3) The simplified radical form is $\sqrt{15x^8}=\sqrt{15}x^4$

4) The simplified radical form is $\sqrt{36x^7}=6x^3\sqrt{x}$

Step-by-step explanation:

1) Given expression is $\sqrt{36x^2}$

To find the simplified radical form of the given expression :

$\sqrt{36x^2}$

$=\sqrt{36\times x^2}$

$=\sqrt{36}\times \sqrt{x^2}$

$=\sqrt{6\times 6}\times \sqrt{x\times x}$

$=6\times x$

$\sqrt{36x^2}=6x$

Therefore the simplified radical form is $\sqrt{36x^2}=6x$

2)Given expression is $\sqrt{72x^3}$

To find the simplified radical form of the given expression :

$\sqrt{72x^3}$

$=\sqrt{72\times x^3}$

$=\sqrt{72}\times \sqrt{x^3}$

$=\sqrt{9\times 8}\times \sqrt{x\times x\times x}$

$=\sqrt{9}\times \sqrt{8}\times x\sqrt{x}$

$=3\times 2\sqrt{2}\times x\sqrt{x}$

$\sqrt{72x^3}=6x\sqrt{2x}$

Therefore the simplified radical form is $\sqrt{72x^3}=6x\sqrt{2x}$

3) Given expression is $\sqrt{15x^8}$

To find the simplified radical form of the given expression :

$\sqrt{15x^8}$

$=\sqrt{15\times x^8}$

$=\sqrt{15}\times \sqrt{x^8}$

$=\sqrt{5\times 3}\times \sqrt{x^4\times x^4}$

$=\sqrt{15}\times x^4$

$\sqrt{15x^8}=\sqrt{15}x^4$

Therefore the simplified radical form is $\sqrt{15x^8}=\sqrt{15}x^4$

4) Given expression is $\sqrt{36x^7}$

To find the simplified radical form of the given expression :

$\sqrt{36x^7}$

$=\sqrt{36\times x^7}$

$=\sqrt{36}\times \sqrt{x^7}$

$=\sqrt{6\times 6}\times \sqrt{x^3\times x^3\times x}$

$=6\times x^3\sqrt{x}$

$\sqrt{36x^7}=6x^3\sqrt{x}$

Therefore the simplified radical form is $\sqrt{36x^7}=6x^3\sqrt{x}$

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pav-90 [236]

Answer:

x y

9 18

5 10

1 2

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

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Solve the quadratic equation: -x^2+8x=7

Burka [1]

Answer:

Step-by-step explanation:

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