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netineya [11]
3 years ago
14

In the basketball game, you made 12 baskets and scored 19 points. How many 2-point shots did you make? How many free throws did

you make?​
Mathematics
2 answers:
storchak [24]3 years ago
6 0

Answer:

0.5

Step-by-step explanation:

Cloud [144]3 years ago
6 0

Answer:12 baskets - 19pts

2×7= 14pts

1×5= 5pts

Therefore: (7+5) baskets= (14+5)pts

> 12 baskets = 19pts

Step-by-step explanation:

For a 2-point shots to make 14pts, there will be 7 baskets/throws.

A free throw shot is 1pts, so there has to be about five (5) free throws which will make 5pts.

Therefore, there will be (7+5 baskets) 12 shots in total.

2-point shots = 7

1-free throws = 5

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ivanzaharov [21]

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5 0
3 years ago
Read 2 more answers
Plz help 10 point
cestrela7 [59]

Answer:

  D.  -5

Step-by-step explanation:

  \dfrac{-\dfrac{15}{5}}{\dfrac{3}{5}}=\dfrac{-15}{3}=\boxed{-5}

The compound fraction is easily simplified because both numerator and denominator have 5 in their denominator. Hence the ratio is the ratio of the numerators.

When an odd number of minus signs is involved in multiplication or division, the result is negative.

5 0
3 years ago
PLEASE help me with this question! This is URGENT!
gavmur [86]

Answer:

\frac{1}{3x+52}

Step-by-step explanation:

We begin with the expression

\frac{\frac{1}{x^2+51x+50} }{\frac{2}{x+50}+\frac{1}{x+1} }

First, we can split this into the product of two fractions

\frac{1}{x^2+51x+50} *(\frac{1}{\frac{2}{x+50}+\frac{1}{x+1}} )

Now, we can factor the denominator of the first fraction.

\frac{1}{(x+1)(x+50)} *(\frac{1}{\frac{2}{x+50}+\frac{1}{x+1}} )

Next, we need to create a common denominator for the second fraction

\frac{2}{x+50}+\frac{1}{x+1}\\\\\frac{2}{x+50}*\frac{x+1}{x+1} +\frac{1}{x+1}*\frac{x+50}{x+50} \\\\\frac{2x+2}{(x+1)(x+50)} + \frac{x+50}{(x+1)(x+50)}\\\\ \frac{3x+52}{(x+1)(x+50)}

Now to return this portion to the denominator of the second fraction.

\frac{1}{(x+1)(x+50)} *(\frac{1}{\frac{3x+52}{(x+1)(x+50)} } )

Dividing by a fraction is the same as multiplying as the reciprocal of the fraction, so the second fraction becomes

\frac{1}{(x+1)(x+50)} *\frac{(x+1)(x+50)}{3x+52}

Now to reduce this expression by canceling out (x+1)(x+5)

\frac{(x+1)(x+50)}{(x+1)(x+50)(3x+52)}\\\\\frac{1}{3x+52}

3 0
3 years ago
Please complete the system of equations.
kogti [31]

Answer:

x=-1,y=0

Step-by-step explanation:

-10y+9x=-9

10y+5x=-5

14x=-14

x=-1

-10y-9=-9

y=0

8 0
3 years ago
How would you find x?
olga nikolaevna [1]

Answer:

the value of x = 61

I hope it's helps you

5 0
3 years ago
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