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MatroZZZ [7]
3 years ago
10

What is the value of log2 18 rounded to the nearest hundredth?

Mathematics
1 answer:
Lisa [10]3 years ago
7 0
0.843 that should be rounded from the nearest 100th
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How much Zn and how much HCl should be used to produce 1.5 g ZnCl2
tatuchka [14]

Answer:

  • 0.71963 g of Zn
  • 0.80256 g of HCl

Step-by-step explanation:

The required mass of reactants can be computed from the number of moles of product.

  moles of ZnCl₂ = (1.5 g)/(136.282 g) ≈ 0.0110066 moles

Then the mass of Zn required is ...

  mass of Zn = (0.0110066 mol)(65.382 g/mol) = 0.71963 g

Two moles of HCl are used in the reaction with each mole of Zn, so the mass of HCl required is ...

  mass of HCl = 2(0.0110066 mol)(36.458 g/mol) = 0.80256 g

_____

<em>Comment</em>

The discrepancy in the last two decimal places of the weights above versus the calculator output below comes from rounding of moles of Zn to 4 significant digits, instead of 5 or more. The number of moles of ZnCl₂ is closer to 0.0110066.

4 0
3 years ago
I need HELPPPPPP PLEASEEEEEE!!!!!!!!~!!!!!!
Sedaia [141]

Answer:

Starting from the left.

4 × 3

5 × 5

2 × 5

4 × 5

4 × 4

1.5 × 2

Step-by-step explanation:

Divide all dimensions by 8.

5 0
3 years ago
Which is closest to the distance between the two points on the graph?
SVETLANKA909090 [29]

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25

Step-by-step explanation:

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Complete the statement with the choice that best
chubhunter [2.5K]

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Factors of the constant term

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Consider the sequence 3, 6, 12, 24, 48, .... (a) Write a recursive rule to represent the sequence. (b) Write an explicit rule to
saveliy_v [14]

Answer:

  a. a[1] = 3; a[n] = 2a[n-1]

  b. a[n] = 3·2^(n-1)

  c. a[15] = 49,152

Step-by-step explanation:

Each term of the given sequence is 2 times the previous term. (This description is the basis of the recursive formula.) That is, the terms of the given sequence have a common ratio of 2. This means the sequence is geometric, so the formulas for explicit and recursive rules for a geometric sequence apply.

The first term is 3, and the common ratio is 2.

<h3>(a)</h3>

The recursive rule is ...

  a[1] = 3

  a[n] = 2×a[n-1]

__

<h3>(b)</h3>

The explicit rule is ...

  a[n] = a[1]×r^(n-1)

  a[n] = 3×2^(n-1)

__

<h3>(c)</h3>

The 15th term is ...

  a[15] = 3×2^(15-1) = 3×2^14

  a[15] = 49,152

5 0
3 years ago
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