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Rashid [163]
3 years ago
13

(True/False) Utilizing a higher bandwidth can support a larger volume of data (in bits per second) to be transmitted than a lowe

r bandwidth.
Computers and Technology
2 answers:
saw5 [17]3 years ago
7 0

Answer:

True

Explanation:

Bandwidth in information technology is defined as the number of transmitted bits in one seconds. It determines the speed of a transmission link or channel. A link can transmit data of a few bits to hundreds of gigabyte in a second.

A higher bandwidth channel can transmit a large number of data per second and can transmit a large chunk not data faster than a lower bandwidth channel.

lions [1.4K]3 years ago
3 0

Answer:

True

Explanation:

Bandwidth refers to the maximum data transfer rate across the communication media it refers to the amount of information sent for unit time and it's not related to the speed at which data is transferred (latency) but rather the amount of information. As an analogy imagine a full-pipe, the width of the pipe is related to the amount of water per unit time across the pipe (bandwidth).

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Which type of chart is used to chart progress over time?
Morgarella [4.7K]

Answer: Timeline

Explanation:

6 0
3 years ago
2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of
allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

=  n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0
3 years ago
What does this mean, i am so confused- Explain the importance of identifying the purpose/use for pre-production documents
irina1246 [14]

Answer: These are mostly used in interior design, fashion design, and advertising. they are often used to generate ideas for a client to meet their approval before making the final product. It can help in terms of planning because it could be used to create a design or a theme.

Explanation: yw

4 0
3 years ago
Where is the start frame delimiter found in the Ethernet frame
Ksju [112]
Answer: The SFD is the eight-bit (one-byte) value that marks the end of the preamble, which is the first field of an Ethernet packet, and indicates the beginning of the Ethernet frame.
8 0
3 years ago
When did the first usb flash drive appear on the retail market? Which company developed this storage medium?
jeka57 [31]

The first commercially-available USB flash drive was the "ThumbDrive," produced by Singapore company Trek Technology in 2000. The drive had capacities of

8 MB

64 MB

1.44 MB

256 MB

7 0
3 years ago
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