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3 years ago

Which of the following savings vehicles usually requires a high minimum balance

1 answer:

7 0

A Savings Vehicle is an effective way to hold your savings. It could be a savings account. But some requires a high minimum balance such as Certificate of Deposit (CD). It is generally issued by commercial banks. It is a time deposit too and restricts you from withdrawing funds.

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Find the root using bisection method with initials 1 and 2 for function 0.005(e^(2x))cos(x) in matlab and error 1e-10?

frutty [35]

Answer:

The root is:

$c=1.5708$

Explanation:

Use this script in Matlab:

-------------------------------------------------------------------------------------

function [c, err, yc] = bisect (f, a, b, delta)

% f the function introduce as n anonymous function

% - a y b are the initial and the final value respectively

% - delta is the tolerance or error.

% - c is the root

% - yc = f(c)

% - err is the stimated error for c

ya = feval(f, a);

yb = feval(f, b);

if ya*yb > 0, return, end

max1 = 1 + round((log(b-a) - log(delta)) / log(2));

for k = 1:max1

c = (a + b) / 2;

yc = feval(f, c);

if yc == 0

a = c;

b = c;

elseif yb*yc > 0

b = c;

yb = yc;

else

a = c;

ya = yc;

end

if b-a < delta, break, end

end

c = (a + b) / 2;

err = abs(b - a);

yc = feval(f, c);

-------------------------------------------------------------------------------------

Enter the function in matlab like this:

f= @(x) 0.005*(exp(2*x)*cos(x))

You should get this result:

f =

function_handle with value:

@(x)0.005*(exp(2*x)*cos(x))

Now run the code like this:

[c, err, yc] = bisect (f, 1, 2, 1e-10)

You should get this result:

c =

1.5708

err =

5.8208e-11

yc =

-3.0708e-12

In addition, you can use the plot function to verify your results:

fplot(f,[1,2])

grid on

5 0

3 years ago

Write code that does the following: opens an output file with the filename number_list.txt, uses a loop to write the numbers 1 t

Lady_Fox [76]

Answer:

# create the file

filename = "Testfile.txt"

# for writing, we create the output file:

outPutfile = open(filename, "w")

# Writing numbers from 1-100

for item in range(1,101):

outPutfile.write((str)(item))

outPutfile.close()

# printing the contents to verify it worked correctly

infile = open(filename, "r") #note the "r" indicates the mode

fileContents = infile.read()

infile.close()

print(fileContents)

Explanation:

Define the working file fileName = TestFile
Create the output file for writting outPutfile = open(filename, "w")
Use a for loop to write numbers from 1-100 to the file outPutfile.write((str)(item))
Close the file outPutfile.close()
You may open the file read its content and print the contents to verify it worked correctly