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garik1379 [7]
3 years ago
13

If U is between T and B, find TU. TU = 6x + 16, UB = 2x – 1, TB = 55.

Mathematics
1 answer:
enot [183]3 years ago
3 0

Answer:

TU = 46

Step-by-step explanation:

Here, we are concerned with finding TU

Mathematically;

Since U is between T and B, by convention;

TB = TU + UB

Substituting the values so we can find x;

55 = 6x + 16 + 2x -1

55 = 6x + 2x + 16-1

55 = 8x + 15

8x = 55-15

8x = 40

x = 40/8

x = 5

But TU = 6x + 16; substitute the value of 5 for x

TU = 6(5) + 16

TU = 30 + 16

TU = 46

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( -2 ) × (4.5) equals
KatRina [158]

Answer:

-9

Step-by-step explanation:

A negative times a positive make a negative outcome. (Using rule of integers)

2×4.5=9

Make it negative to get -9

3 0
3 years ago
Read 2 more answers
Find the length of the third side. If necessary, round to the nearest tenth.
joja [24]

Answer: 5

Step-by-step explanation:

use formula a^2 + b^2 = c^2

a^2 + 12^2 = 13^2

a^2 + 144 = 169

       - 144   -144

a^2 = 25

sqrt   sqrt

a = sqrt (25)

a = 5

8 0
3 years ago
Can someone pls show how to do this is with explanation
Keith_Richards [23]
1m = 100 cm
0.05 m = 5cm
1 km = 10000 cm
0.00005 km = 5 cm
Yes they are equal

(Mark me the brainliest if this has helped!)
4 0
3 years ago
Guys please help! In triangle CDE, the measure of angle C is 90 degrees, side CD is 15 and DE is 3 more than CE. Find the length
AURORKA [14]
You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)

your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°

-> insert those values, with c substituted with b+3 to remove c

c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE

DE=CE+3=36+3=39
4 0
4 years ago
What is the geometric mean of 5 and 7?
Harman [31]
<h3>Geometric mean of 5 and 7 is 5.9161</h3>

<em><u>Solution:</u></em>

Given that,

We have to find the geometric mean of 5 and 7

The geometric mean of two numbers a and b is the square root of product of a and b

Which means,

Geometric\ mean = \sqrt{ab}

<h3><u>Geometric mean of 5 and 7</u></h3>

Geometric\ mean = \sqrt{5 \times 7}\\\\Geometric\ mean = \sqrt{35}\\\\Geometric\ mean = 5.9161

Thus geometric mean of 5 and 7 is 5.9161

5 0
3 years ago
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