4, there is 3 radii OA, OC and OB
2nd choice
5. there is one chord BC
first choice
6. 3 central angles:
AOC, AOB, BOC
first choice
Answer:
6.25-1.75
Step-by-step explanation:
Step-by-step explanation:
Monique had 6 dollars. She found 25 cents and then bought a book
25 cents = 0.25 dollars
Total dollar she had= 6 + 0.25= 6.25 dollars
Let x be the cost of a book
She ended up with 7 quarters. Convert quarter into dollars
1 quarter = 0.25 dollars
7 quarters = 7 times 0.25=1.75 dollars
So she ended up with 1.75 dollars
Amount she had at the beginning - the cost of book = amount ended up
Number of dollars spent on the book = Amount she had - amount ended
Number of dollars spent on the book=
6.25-1.75
Answer:
A dilation stretches or shrinks the original figure. A description of a dilation includes the scale factor (or ratio) and the center of the dilation. The center of dilation is a fixed point in the plane. If the scale factor is greater than 1, the image is an enlargement (a stretch).
Step-by-step explanation:
(g+f)(x) ie option B
-2+1 = -1
1-2 = -1
4-5 = - 1
This is a little long, but it gets you there.
- ΔEBH ≅ ΔEBC . . . . HA theorem
- EH ≅ EC . . . . . . . . . CPCTC
- ∠ECH ≅ ∠EHC . . . base angles of isosceles ΔEHC
- ΔAHE ~ ΔDGB ~ ΔACB . . . . AA similarity
- ∠AEH ≅ ∠ABC . . . corresponding angles of similar triangle
- ∠AEH = ∠ECH + ∠EHC = 2∠ECH . . . external angle is equal to the sum of opposite internal angles (of ΔECH)
- ΔDAC ≅ ΔDAG . . . HA theorem
- DC ≅ DG . . . . . . . . . CPCTC
- ∠DCG ≅ ∠DGC . . . base angles of isosceles ΔDGC
- ∠BDG ≅ ∠BAC . . . .corresponding angles of similar triangles
- ∠BDG = ∠DCG + ∠DGC = 2∠DCG . . . external angle is equal to the sum of opposite internal angles (of ΔDCG)
- ∠BAC + ∠ACB + ∠ABC = 180° . . . . sum of angles of a triangle
- (∠BAC)/2 + (∠ACB)/2 + (∠ABC)/2 = 90° . . . . division property of equality (divide equation of 12 by 2)
- ∠DCG + 45° + ∠ECH = 90° . . . . substitute (∠BAC)/2 = (∠BDG)/2 = ∠DCG (from 10 and 11); substitute (∠ABC)/2 = (∠AEH)/2 = ∠ECH (from 5 and 6)
- This equation represents the sum of angles at point C: ∠DCG + ∠HCG + ∠ECH = 90°, ∴ ∠HCG = 45° . . . . subtraction property of equality, transitive property of equality. (Subtract ∠DCG+∠ECH from both equations (14 and 15).)
