All categories

3 years ago

Which function has the smallest minimum? (5 points)

Mathematics

1 answer:

Andrej [43]3 years ago

4 0

f(x) has the smallest minimum. The minimum value of f(x) is -3

The largest sin(x) can get is 1.
This applies to sin(2x-pi) as well. So f(x) is as small as -5*(1)+2 = -5+2 = -3.
You can see this each time the red curve bottoms out at y = -3.

The smallest that g(x) can get is y = -2 as shown at the vertex (3,-2)

The smallest that h(x) can get is y = 3 as shown by the point (1,3)

See the attachment for a visual comparison of the three functions.

You might be interested in

Hi- I need help please to get my HS diploma...did not graduate :(

andrew-mc [135]

The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
$\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}$

where:

The divisor = 2x -3

Using the long division method, we have:

$\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}$

$\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}$

$\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}$

$\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}$

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

#SPJ1

8 0

2 years ago

during a state fair weekend the state gives away free admission 165 person that enters thefair on saturday 7925 people attend th

yKpoI14uk [10]

165 people get free admission

4 0

3 years ago

Read 2 more answers

Pentagon with a side of 6 ft

TEA [102]

I think it would be 56.

3 0

3 years ago

1 1/4 + ( 3 2/3 + 5 3/4)

Dmitrij [34]

Answer:

10.6

10+ 2/3

Step-by-step explanation:

6 0

4 years ago

Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$

Thus, the expected monetary value of a single roll is $1.17.

7 0

3 years ago