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2 years ago

8

Which function has the smallest minimum? (5 points)

1 answer:

Andrej [43]2 years ago

4 0

f(x) has the smallest minimum. The minimum value of f(x) is -3

The largest sin(x) can get is 1.
This applies to sin(2x-pi) as well. So f(x) is as small as -5*(1)+2 = -5+2 = -3.
You can see this each time the red curve bottoms out at y = -3.

The smallest that g(x) can get is y = -2 as shown at the vertex (3,-2)

The smallest that h(x) can get is y = 3 as shown by the point (1,3)

See the attachment for a visual comparison of the three functions.

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the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai

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Let $X$ be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

$P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10$

where $Z$ follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

$P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)$

where $F_Z(z)=P(Z\le z)$ denotes the CDF of $Z$ , and $F_Z^{-1}$ denotes the inverse CDF. We have

$z_1=F_Z^{-1}(0.90)\approx1.2816$

Similarly, because 20% of students obtain less than 40 marks, we have

$P(X$

so that

$P(Z$

Then $\mu,\sigma$ are such that

$\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma$

$\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma$

and we find

$\mu\approx53.8739,\sigma\approx16.4848$

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