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3 years ago

8

Which function has the smallest minimum? (5 points)

1 answer:

Andrej [43]3 years ago

4 0

f(x) has the smallest minimum. The minimum value of f(x) is -3

The largest sin(x) can get is 1.
This applies to sin(2x-pi) as well. So f(x) is as small as -5*(1)+2 = -5+2 = -3.
You can see this each time the red curve bottoms out at y = -3.

The smallest that g(x) can get is y = -2 as shown at the vertex (3,-2)

The smallest that h(x) can get is y = 3 as shown by the point (1,3)

See the attachment for a visual comparison of the three functions.

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A cylinder with radius 3 feet and height 5 feet is shown.

Leviafan [203]

Answer:

The volume of the cylinder is <u>141.23 cubic feet </u>

Step by step explanation :

<u>Given</u>-

Radius of cylinder = 3 feet
Height of cylinder = 5 feet

Now, we know that

<h3> $\boxed {\mathfrak \red{ volume \: of \: cylinder = \pi {r}^{2} h}}$ </h3>

where, r is the radius of the cylinder & h is the height of the cylinder.

Now,

Volume of the cylinder = $\frac{22}{7} \times {3}^{2} \times 5$

$= \frac{22}{7} \times 3 \times 3 \times 5$

<h3> $= \frac{990}{7}$ </h3>

$= 141.428571$ ( approximately )

$= \boxed{ 141.43 \: \mathfrak { {ft}^{3}} }$

6 0

2 years ago

2. Jessica is a waitress. Her customer’s bills totaled $300. She earned $45 in tips. What percent did her customers tip her? ___

zepelin [54]

Answer:

15%

Step-by-step explanation:

$45/$300 = 0.15 = 15%

4 0

3 years ago

Read 2 more answers

a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei

Masteriza [31]

Answer:

The weight of a small box = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) = 5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) = 3 n

Here, 3 large boxes + 5 small boxes = of 123 kilograms

⇒ 5 m + 3 n = 123 .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) = 2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) = 12 n

Here, 12 large boxes + 2 small boxes = 249 kilograms

⇒ 2 m+ 12 n = 249 .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5 m + 3 n = 123 x (2)

2 m+ 12 n = 249 x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n = -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5 m + 3 n = 123

So, 5 m = 123 -3 (18.5) = 123 - 55.5 = 67.5

⇒ m = 13.5

Hence, the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg = 18.5 kg

8 0

3 years ago

45 POINTS!! PLEASE HELP!! Im struggling on a math assignment and if I fail the class I can't graduate. I need someone to create

Andrews [41]

Use Excel graphing. Then make histogram (a graph that represents values with columns)

6 0

3 years ago

When as rate, 100 miles in 5 hours would be ????? miles per hour

koban [17]

Answer:

20

Step-by-step explanation:

5 divided by 100 = 20

3 0

3 years ago

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