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Kobotan [32]
3 years ago
8

HELP QUICKKKKKK PLEASEEE

Mathematics
1 answer:
Misha Larkins [42]3 years ago
8 0
The answer is d because it 0 has more than one outcome and 0 needs to only have one outcome for it to be a function
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I need help w/ math due asap plzz
julia-pushkina [17]

Answer:

The answer is D

Step-by-step explanation:

You multiply by 2  19 x 2 = 38 38 x 2 = 76  76 x 2 = 152

then 152 x 2 = D 304

3 0
3 years ago
How do i solve this system of equations
WITCHER [35]
22, i think because 3 times 3= 9, and 9 times 3 minus 5= 22

8 0
3 years ago
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7x^2=9+x what are the values of x<br><br>Will give medal and points
DENIUS [597]
7x² = 9 + x   Subtract x from both sides
7x² - x = 9    Subtract 9 from both sides
7x² - x - 9 = 0   Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = \frac{-b \pm  \sqrt{b^2 - 4ac} }{2a}   Plug in the a, b, and c values
x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
x = \frac{1 \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Square -1
x = \frac{1 \pm  \sqrt{1 - 4(7)(-9)} }{2(7)}   Multiply 7 and -9
x = \frac{1 \pm  \sqrt{1 - 4(-63} }{2(7)}   Multiply -4 and -63
x = \frac{1 \pm  \sqrt{1 + 252} }{2(7)}   Multiply 2 and 7
x = \frac{1 \pm  \sqrt{1 + 252} }{14}   Add 1 and 252
x = \frac{1 \pm  \sqrt{253} }{14}   Split up the \pm
x = \left \{ {{ \frac{1 +  \sqrt{253} }{14} } \atop { \frac{1 -  \sqrt{253} }{14} }} \right.
The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
x ≈ \left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.   Divide
x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
</span>
7 0
3 years ago
A radar gun was used to record the speed of a swimmer (in meters per second) during selected times in the first 2 seconds of a r
Natalka [10]
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]

the area of each trapezoid is (v(t1)+v(t2))/2 times width

for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8

2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24

3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75

4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7

add them all up
0.8+2.24+1.75+0.7=5.49

5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
8 0
3 years ago
Write the subtraction expression for the number line shown.
Scorpion4ik [409]

Answer is

0-4-9

start from zero then count

7 0
3 years ago
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