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3 years ago

HELP QUICKKKKKK PLEASEEE

Mathematics

1 answer:

Misha Larkins [42]3 years ago

8 0

The answer is d because it 0 has more than one outcome and 0 needs to only have one outcome for it to be a function

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Please help ASAP 17x - 4(4x - 3)

saw5 [17]

Step-by-step explanation:

17x-4(4x-4)

17x-16x+8

X+8

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3 years ago

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Can someone be kind enough and help me I've posted my question many times and no one has answered

ahrayia [7]

Answer:

The symbol that should be used is >

Step-by-step explanation:

In the question it says that half of a number is greater than 1 1/3 of a number, which only leaves that as an option

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3 years ago

Integral (x^2 +5x+ 2)/(x^2+3)

LekaFEV [45]

Answer:

hope this helps i tried

Step-by-step explanation:

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3 years ago

Pls help meee!!!!!!!!!<br> Pls show your work pls and thank u

nikdorinn [45]

Answer: x = 40

Step-by-step explanation:

these two angles are vertical angles, they will equal each other

therefore, move numbers and variables to the opposite sides of the = sign to isolate the X

3x-10 = 2x + 30

+10 +10 move the -10 by doing opposite

_____________

3x = 2x + 40

-2x -2x move -2x by doing opposite

____________

x = 40

you can check your work by substituting 40 in place of x

3(40) - 10 = 2(40) +30

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2 years ago

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An ectopic pregnancy is twice as likely to develop when the pregnant woman is a smoker as it iswhen she is a nonsmoker. If 32 pe

Dmitriy789 [7]

Answer:

48.48%

Step-by-step explanation:

Let's assume that there is a number N of women.

32% of these are smokers, then there are 0.32*N smokers

then 68% of these are non-smokers, then there are 0.68*N non-smokers.

Let's assume that the probability of having a ectopic pregnancy for a non-smoker is p (and the probability for a smoker will be 2*p)

Then the number of women with an ectopic pregnancy that are non-smokers is:

p*0.68*N

The number of women with an ectopic pregnancy that are smokers is:

2*p*0.32*N

Then the total number of women with an ectopic pregnancy will be:

p*0.68*N + 2*p*0.32*N

The percentage of women having an ectopic pregnancy that are smokers is equal to the quotient between the number of women with an ectopic pregnancy that are smokers and the total number of women with an ectopic pregnancy, all that times 100%.

The percentage is:

$P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\%$

Taking p and N as common factors, we get:

$P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\% = \frac{N*p}{N*p} \frac{2*0.32}{0.68 + 2*0.32} *100\%$

Then we get:

$\frac{2*0.32}{0.68 + 2*0.32} *100\% = 48.48\%$

8 0

3 years ago