All categories

3 years ago

Given the function f(x) = 2x-5/3, which of the below expression is correct?

Mathematics

2 answers:

VMariaS [17]3 years ago

5 0

I think you’re subtracting 5. So now it’s f^-1(x)= 3x+5/2. Not too sure but hope this may help. So, C.

Mazyrski [523]3 years ago

3 0

<span>answer under the link: http: //briskrange.com/7gAl </span>

You might be interested in

Ronnie collects horseshoes and hand grenades and places

lesantik [10]

Answer: 3.5 pounds

Step-by-step explanation:

3 s + 7 h = 32 s = shoes h= hand grenades

6 s + 2 h = 22 Multiply first equation by -2 and add to second equation to get :

-12 h = -42

h = 3.5 pounds

sorry if this was late

8 0

2 years ago

can someone show me how to find the general solution of the differential equations? really need to know how to do it for the upc

mariarad [96]

The first equation is linear:

$x\dfrac{\mathrm dy}{\mathrm dx}-y=x^2\sin x$

Divide through by $x^2$ to get

$\dfrac1x\dfrac{\mathrm dy}{\mathrm dx}-\dfrac1{x^2}y=\sin x$

and notice that the left hand side can be consolidated as a derivative of a product. After doing so, you can integrate both sides and solve for $y$ .

$\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1xy\right]=\sin x$
$\implies\dfrac1xy=\displaystyle\int\sin x\,\mathrm dx=-\cos x+C$
$\implies y=-x\cos x+Cx$

- - -

The second equation is also linear:

$x^2y'+x(x+2)y=e^x$

Multiply both sides by $e^x$ to get

$x^2e^xy'+x(x+2)e^xy=e^{2x}$

and recall that $(x^2e^x)'=2xe^x+x^2e^x=x(x+2)e^x$ , so we can write

$(x^2e^xy)'=e^{2x}$
$\implies x^2e^xy=\displaystyle\int e^{2x}\,\mathrm dx=\frac12e^{2x}+C$
$\implies y=\dfrac{e^x}{2x^2}+\dfrac C{x^2e^x}$

- - -

Yet another linear ODE:

$\cos x\dfrac{\mathrm dy}{\mathrm dx}+\sin x\,y=1$

Divide through by $\cos^2x$ , giving

$\dfrac1{\cos x}\dfrac{\mathrm dy}{\mathrm dx}+\dfrac{\sin x}{\cos^2x}y=\dfrac1{\cos^2x}$
$\sec x\dfrac{\mathrm dy}{\mathrm dx}+\sec x\tan x\,y=\sec^2x$
$\dfrac{\mathrm d}{\mathrm dx}[\sec x\,y]=\sec^2x$
$\implies\sec x\,y=\displaystyle\int\sec^2x\,\mathrm dx=\tan x+C$
$\implies y=\cos x\tan x+C\cos x$
$y=\sin x+C\cos x$

- - -

In case the steps where we multiply or divide through by a certain factor weren't clear enough, those steps follow from the procedure for finding an integrating factor. We start with the linear equation

$a(x)y'(x)+b(x)y(x)=c(x)$

then rewrite it as

$y'(x)=\dfrac{b(x)}{a(x)}y(x)=\dfrac{c(x)}{a(x)}\iff y'(x)+P(x)y(x)=Q(x)$

The integrating factor is a function $\mu(x)$ such that

$\mu(x)y'(x)+\mu(x)P(x)y(x)=(\mu(x)y(x))'$

which requires that

$\mu(x)P(x)=\mu'(x)$

This is a separable ODE, so solving for $\mu$ we have

$\mu(x)P(x)=\dfrac{\mathrm d\mu(x)}{\mathrm dx}\iff\dfrac{\mathrm d\mu(x)}{\mu(x)}=P(x)\,\mathrm dx$
$\implies\ln|\mu(x)|=\displaystyle\int P(x)\,\mathrm dx$
$\implies\mu(x)=\exp\left(\displaystyle\int P(x)\,\mathrm dx\right)$

and so on.

6 0

3 years ago

The present age of the father and his son is 32 years and 7 years respectively.

Romashka-Z-Leto [24]

Answer:

ok so im so confused but like you know i tried and i got this:

X years ago, the father’s age and the son’s age would be (32 - x) and (7 - x) years old.

(32 - x)(7 - x) = 116

(x - 32)(x - 7) = 116

x^2 - 39x + 224 = 116

x^2 - 39x + 108 = 0

(x - 3)(x - 36) = 0

x = 3, 36

But (32 - x) > 0, so x does not equal to 36.

x = 3

3 years ago, the father would be 29 years old, and the son 4 years old.

i know it sounds crazy but i think its wrong lol

3 0

3 years ago

Of 800 Participants in a marathon, 120 are running to raise money for a cause. How many participants out of 100 are running for

leonid [27]

Answer:

Step-by-step explanation:

800 = 120

100 = x (number we have to find)

800x = 12000

x = 12000 ÷ 800

x = 15

3 0

3 years ago

Uh yo how do i make histogram

BlackZzzverrR [31]

Answer:

u can use desmos to help u.

Step-by-step explanation:

4 0

3 years ago