Negative is the opposite of positive, so the only true opposites are. -2,2 8,-8
Answer:
The required polynomial is 
.
Step-by-step explanation:
If a polynomial has degree n and 
are zeroes of the polynomial, then the polynomial is defined as
It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.
According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.
Since 3-3i is zero, therefore 3+3i is also a zero.
Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is
![[a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5Ba%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
![[i^2=-1]](https://tex.z-dn.net/?f=%5Bi%5E2%3D-1%5D)
Therefore the required polynomial is .
The coordinate of the midpoint of line segment LT is determined as: -12.
<h3>How to Find the Coordinate of the Midpoint of a Line Segment?</h3>
The midpoint of a line segment is the point where the distance between the endpoints of the line segment are equidistant. The distance from that midpoint to each endpoint is the same.
Given the following:
- Coordinate of point L is: -35
- Coordinate of point T is: 11
Distance from point L to T = |-35 - 11| = 46 units.
Half of 46 units would be: 46/2 = 23 units.
This means that, both point L and point T are 23 units from the midpoint of segment LT.
Thus, the coordinate of the midpoint would be 23 units from -35 = -35 + 23 = -12
Or 23 units from the midpoint to point T = 11 - 23 = -12
Therefore, the coordinate of the midpoint of line segment LT is determined as: -12.
Learn more about the midpoint of a segment on:
brainly.com/question/19149725
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Answer:
Rational form:
399/100 = 3 + 99/100
Continued fraction:
[3; 1, 99]
Possible closed forms:
399/100 = 3.99
log(54)≈3.988984
8/(3 π) + π≈3.9904190
1/2 (e! + 1 + e)≈3.989551
-(sqrt(3) - 3) π≈3.983379
(14 π)/11≈3.9983906
25/(2 π)≈3.978873
(81 π)/64≈3.976078
(2 e^2)/(1 + e)≈3.974446
(π π! + 2 + π + π^2)/(3 π)≈3.988765
2 π - log(4) - 3 log(π) + 2 tan^(-1)(π)≈3.987955
2 - 1/(3 π) + (2 π)/3≈3.988291
Step-by-step explanation:
Answer:
2 bears in 2020.
Step-by-step explanation:
We have been given that a new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.
We will use exponential decay formula to solve our given problem as:
, where,
y = Final quantity,
a = Initial value,
r = Decay rate in decimal form,
x = Time
Upon substituting our given values in above formula, we will get:
, where x corresponds to year 2000.
To find the population in 2020, we will substitute 
in our equation as:
Therefore, 2 bears are there predicted to be in 2020.
Since population is decreasing so population is best described as exponential decay.
