Question

Cynthia is planning a party. for entertainment, she has designed a game that involves spinning two spinners. if the sum of the numbers on the spinners is 10 or greater, the guests can choose a prize from a basket of candy bars. if the sum is less than 10, then the guest will be thrown in the pool. she has two possible pairs of spinners, shown below. for each pair of spinners, determine the probability of getting tossed in the pool. assume that spinners b, c, and d are equally subdivided.

Answer 1

The correct statement of the problem is attached

Spinner A: 4 parts, 3/4 is 1, 1/4 is 3.----------1  1  1  3  
Spinner B: 3 parts, 1/3 is 5, 1/3 is 7, 1/3 is 9--------5  7  9

The combinations of the two spinners are
1 and 5
1 and 7
1 and 9
3 and 5
3 and 7
3 and 9

cases get you thrown in the pool
1 and 5
1 and 7
3 and 5

calculation of the probabilities
1 and 5--------3/4*1/3 = 1/4
1 and 7--------3/4*1/3 = 1/4
3 and 5--------1/4*1/3 = 1/12
1/4+1/4+1/12=7/12-----------58.33%

probabilities that the guests will be thrown in the pool--------58.33%