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3 years ago

4n-3=-2n+9 What is the value of the variable 'n'?

1 answer:

7 0

4n - 3= -2n + 9
add 3n to both sides

4n= -2n +12
add 2n to both sides

6n= 12
divide both sides by 6

n= 2

Check:
4n-3=-2n+9
4(2)-3= -2(2)+9
8-3= -4+9
5=5

Hope this helps! :)

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2 years ago

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2 years ago

Solve: 4x - 2x + 6 = x + 12 A) x = 6 B) x = 2 C) no solution D) x = −6

Kitty [74]

Answer:

A) x = 6

Step-by-step explanation:

4x - 2x + 6 = x + 12

Combine like terms

2x +6 = x+12

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7 0

2 years ago

Read 2 more answers

Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer

Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

$0=(3x+2)(x-4)$

To solve the given equation, we can use the Zero Product Property according to which if the product A.B = 0, then either A = 0 OR B = 0.

Using this property:

$(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}$

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply $(3x+2)(x-4)$ i.e. $3x^2-12x+2x-8$ = $3x^2-10x-8$

So, the equation becomes:

$0=3x^2-10x-8$

Comparing this equation to standard quadratic equation:

$ax^2+bx+c=0$

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}$

The answer is same from both the approaches.

So, the correct answer is:

C) Both

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2 years ago