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Arlecino [84]
3 years ago
6

A person can pay $8 for a membership to the history museum and then go to the museum for

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0

Answer:

35 visits

Step-by-step explanation:

If the total cost is $43, and the membership is $8 from that, then we can subtract the cost of the membership and it will cost $35 dollars. Then you can go $35/$1 times, which is 35 times.

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Segment XY bisects angle WXZ and angle mZXY = 37 degrees. Find angle mWXY and angle mZXW
Vadim26 [7]

we know that

The angle bisector, is the line or line segment that divides the angle into two equal parts.

So

in this problem

m∠ZXW=m∠WXY+m∠ZXY

m∠WXY=m∠ZXY

Part a) <u>Find the value of m∠WXY</u>

m∠ZXY=37°-----> given value

so

m∠WXY=m∠ZXY=37°

therefore

<u>the answer part a)</u>

The measure of angle WXY is equal to 37°

Part b) <u>Find the value of m∠ZXW</u>

m∠ZXW=m∠WXY+m∠ZXY

m∠ZXW=37°+37°=74°

therefore

<u>the answer part b) is</u>

the measure of angle ZXW is 74 degrees

8 0
3 years ago
4x-12y=-8 what is the answer
umka21 [38]

Answer:

You aren't asked which variable to solve for.

If we're solving for x then

4x = 12y -8

x = 3y - (8/4)

If we're solving for y

-12y = -4x -6

12y = 4x +6

y = (x/3) + (1/2)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A bakery supplier receives an order for 2 Tons of sudar from a bakery chain. The sugar is shipped in crates. Each crate holds ei
stich3 [128]
We know that 1 ton=2000 lbs
we have 2 tons=4,000 lbs
each crate holds 10 lbs of sugar
4,000/10=400 crates
3 0
3 years ago
Trish and Aria are walking to raise money for the school library. Trish has walked 38 miles and walks 10 miles each week. Aria h
schepotkina [342]

Answer:

C. 4 weeks

Step-by-step explanation:

Trish and Aria are walking to raise money for the school library. Trish has walked 38 miles and walks 10 miles each week. Aria has walked 30 miles and walks 12 miles each week

After how many weeks will Trish and Aria have walked the same number of miles? A. 2 weeks B. 3 weeks C. 4 weeks D. 5 weeks

Trish = 38 + 10x

Aria = 30 + 12x

Where,

x = number of weeks

After how many weeks will Trish and Aria have walked the same number of miles?

Equate both equations

38 + 10x = 30 + 12x

38 - 30 = 12x - 10x

8 = 2x

x = 8/2

x = 4 weeks

5 0
3 years ago
You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites. Assume you obtain a r
kicyunya [14]

Answer:

a) 0.2316 = 23.16% probability that 0 carry intestinal parasites.

b) 0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

Step-by-step explanation:

For each trout, there are only two possible outcomes. Either they carry intestinal parasites, or they do not. Trouts are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites.

This means that p = 0.15

Assume you obtain a random sample of 9 individuals from this population:

This means that n = 9

a. Calculate the probability that __ (last digit of your ID number) carry intestinal parasites.

Last digit is 0, so:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316

0.2316 = 23.16% probability that 0 carry intestinal parasites.

b. Calculate the probability that at least two individuals carry intestinal parasites.

This is

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316

P(X = 1) = C_{9,1}.(0.15)^{1}.(0.85)^{8} = 0.3679

P(X < 2) = P(X = 0) + P(X = 1) = 0.2316 + 0.3679 = 0.5995

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5995 = 0.4005

0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

5 0
3 years ago
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