In the given system of equations, the value of x is 7.334 and the value of y is 7.714
<h3>Solving system of linear equations</h3>
From the question, we are to solve the given system of linear equations
The given system of linear equations is
3x + 7y = 76 ------------ (1)
9y + 5y = 108 ------------ (2)
From equation (2), solve for y
9y+ 5y = 108
14y = 108
y = 108/14
y = 7.714
Substitute the value of x into equation (1), to determine the value of x
3x + 7y = 76
3x + 7(7.714) = 76
3x + 53.998 = 76
Subtract 53.998 from both sides of the equation
3x + 53.998 - 53.998 = 76 - 53.998
3x = 22.002
Divide both sides of the equation by 3
3x/3 = 22.002/3
x = 7.334
Therefore,
x = 7.334 and y = 7.714
Learn more on Solving system of linear equations here: brainly.com/question/13729904
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Hang on ,it is already proven through given .
So The proof is of one line only
- ray FEH bisects <DFG (Given)
Hence proved .
Answer:
a. The probability that a customer purchase none of these items is 0.49
b. The probability that a customer purchase exactly 1 of these items would be of 0.28
Step-by-step explanation:
a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:
let A represents suit
B represents shirt
C represents tie
P(A) = 0.22
P(B) = 0.30
P(C) = 0.28
P(A∩B) = 0.11
P(C∩B) = 0.10
P(A∩C) = 0.14
P(A∩B∩C) = 0.06
Therefore, the probability that a customer purchase none of these items we would have to calculate the following:
1 - P(A∪B∪C)
P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)
= 0.22+0.28+0.30-0.11-0.10-0.14+0.06
= 0.51
Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49
The probability that a customer purchase none of these items is 0.49
b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:
= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2 P(A ∩ B ∩ C))
=0.51 -0.23 = 0.28
The probability that a customer purchase exactly 1 of these items would be of 0.28
Answer:
Step-by-step explanation:
Given
Required
Probability of selecting a yellow then orange rock
From the question, we understand that the probability is that of without replacement.
Since the yellow, is first picked.
We need to determine the probability of picking a yellow rock, first.
The rock has reduced by 1;
Next is to determine the probability of picking an orange rock
The required probability is calculated as thus:
