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Bumek [7]
3 years ago
14

Carl's cable company charges $55 for monthly service plus $4 for each pay-per-view movie. Teleview cable company charges $110 pe

r month with no fee for movies. For what number of movies is the cost of Carl's cable company less than the cost of Teleview. ...?
Mathematics
1 answer:
shusha [124]3 years ago
8 0
Let us assume the number of movies for ehich the cost of both companies becomes the same = x
Then
55 + 4x = 110
4x = 110 - 55
4x = 55
x = 55/4
   = 13.75
So
The number <span>number of movies for which the cost of Carl's cable company is less than the cost of Teleview = 13.

I hope the procedure is clear enough for you to understand and this is the answer that you were actually looking for.</span>
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Read 2 more answers
Find the measure of the the sides of DEF then classify it by it sides. <br> D(8,-6) E(-1,-3) F(-2,5)
Mama L [17]

Answer:

Part a) The measure of the sides of triangle DEF are

d_D_E=\sqrt{90}\ units

d_E_F=\sqrt{65}\ units

d_D_F=\sqrt{221}\ units

Part b) Is a scalene triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the coordinates

D(8,-6) E(-1,-3) F(-2,5)

step 1

Find the length side DE

D(8,-6) E(-1,-3)

substitute in the formula

d=\sqrt{(-3+6)^{2}+(-1-8)^{2}}

d=\sqrt{(3)^{2}+(9)^{2}}

d_D_E=\sqrt{90}\ units

step 2

Find the length side EF

E(-1,-3) F(-2,5)

substitute in the formula

d=\sqrt{(5+3)^{2}+(-2+1)^{2}}

d=\sqrt{(8)^{2}+(-1)^{2}}

d_E_F=\sqrt{65}\ units

step 3

Find the length side DF

D(8,-6) F(-2,5)

substitute in the formula

d=\sqrt{(5+6)^{2}+(-2-8)^{2}}

d=\sqrt{(11)^{2}+(-10)^{2}}

d_D_F=\sqrt{221}\ units

step 4

Classify the triangle by the measure of its sides

we have

d_D_E=\sqrt{90}\ units

d_E_F=\sqrt{65}\ units

d_D_F=\sqrt{221}\ units

so

Is a scalene triangle, because is a triangle in which all three sides have different lengths.

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