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Bumek [7]
3 years ago
14

Carl's cable company charges $55 for monthly service plus $4 for each pay-per-view movie. Teleview cable company charges $110 pe

r month with no fee for movies. For what number of movies is the cost of Carl's cable company less than the cost of Teleview. ...?
Mathematics
1 answer:
shusha [124]3 years ago
8 0
Let us assume the number of movies for ehich the cost of both companies becomes the same = x
Then
55 + 4x = 110
4x = 110 - 55
4x = 55
x = 55/4
   = 13.75
So
The number <span>number of movies for which the cost of Carl's cable company is less than the cost of Teleview = 13.

I hope the procedure is clear enough for you to understand and this is the answer that you were actually looking for.</span>
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lbvjy [14]

Answer:

Which question needs to be answered?

5 0
3 years ago
Select the values that make the inequality h &lt; 2 true.
weqwewe [10]

Given:

The inequality is:

h\leq 2

To find:

The values that make the given inequality true.

Solution:

We have,

h\leq 2

It means the value of h must be less than or equal to 2.

In the given options, the list of numbers which are less than or equal to 2 is

-6, -3, -1, 1, 1.9, 1.99, 1.999, 2

The list of numbers which are greater than 2 is

2.001, 2.01, 2.1, 3, 5, 7, 10

Therefore, the first 8 options are correct and the required values are -6, -3, -1, 1, 1.9, 1.99, 1.999, 2.

3 0
3 years ago
What is the area? Bit confused on this one.
DENIUS [597]

Answer:

x² + 8x + 12

Step-by-step explanation:

see

the length of the entire rectangle = x + 6

breadth of the entire rectangle = x + 2

area of a rectangle = length × breadth

= (x + 6)(x + 2)

= x² + 8x + 12

which is the required polynomial in standard form

7 0
3 years ago
Read 2 more answers
-98 = 7t<br> What does t equal
pentagon [3]

Answer:

t = -14

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

-98 = 7t

<u>Step 2: Solve for </u><em><u>t</u></em>

  1. Divide 7 on both sides:                    -14 = t
  2. Rewrite:                                             t = -14

<u>Step 3: Check</u>

<em>Plug in t into the original equation to verify it's a solution.</em>

  1. Substitute in <em>t</em>:                     -98 = 7(-14)
  2. Multiply:                               -98 = -98

Here we see that -98 is equal to -98.

∴ t = -14 is the solution to the equation.

8 0
3 years ago
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What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
2 years ago
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