Answer:
okay.. Questions?????????
Answer:
55.845 u
Explanation:
Fe, iron, has 29 neutrons and a atomic mass of 55.845 u
The concentration of [CI-] : 0.617 M
<h3>Further explanation</h3>
FeCl₃ dissolved in 450 mL of solution(will dissociate )
Reaction
FeCl₃⇒Fe³⁺+3Cl⁻
- mol FeCl₃(MW=162,2 g/mol)
Given:
M = 0.0150 mol/L HF solution
T = 26°C = 299.15 K
π = 0.449 atm
Required:
percent ionization
Solution:
First, we get the van't Hoff factor using this equation:
π = i MRT
0.449 atm = i (0.0150 mol/L) (0.08206 L atm / mol K) (299.15 K)
i = 1.219367
Next, calculate the concentration of the ions and the acid.
We let x = [H+] = [F-]
[HF] = 0.0150 - x
Adding all the concentration and equating to iM
x +x + 0.0150 - x = <span>1.219367 (0.0150)
x = 3.2905 x 10^-3
percent dissociation = (x/M) (100) = (3.2905 x 10-3/0.0150) (100) = 21.94%
Also,
percent dissociation = (i -1) (100) = (</span><span>1.219367 * 1) (100) = 21.94%</span>
