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4 years ago

Need Help please this is the 5th time i asked this question.

2 answers:

7 0

$\bf \begin{array}{cll} wins&\stackrel{t(w)}{tickets}\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1&200\cdot 1.1\\ 2&200\cdot 1.1\cdot 1.1\\ 3&200\cdot 1.1\cdot 1.1\cdot 1.1\\ &200\cdot 1.1^3\\ 4&200\cdot 1.1\cdot 1.1\cdot 1.1\cdot 1.1\\ &200\cdot 1.1^4\\ 5&200\cdot 1.1\cdot 1.1\cdot 1.1\cdot 1.1\cdot 1.1\\ &200\cdot 1.1^5\\ w&200\cdot 1.1^w \end{array}\qquad \qquad \boxed{t(w)=200(1.1)^w}$

Andru [333]4 years ago

3 0

Answer:200(1.1)^w

Step-by-step explanation:

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The graph of y=√x is shifted 2 units up and 5 units left, Which equation represents the new graph?

Zinaida [17]

y = √(x + 5) + 2

<h3>Further explanation</h3>

Given:

The graph of $y = \sqrt{x}$ is

shifted 2 units up, and
5 units left.

Question:

Which equation represents the new graph?

The Process:

The translation is a form of transformation geometry.

Translation (or shifting): moving a graph on an analytic plane without changing its shape.

In general, given the graph of y = f(x) and v > 0, we obtain the graph of:

$\boxed{ \ y = f(x) + v \ }$ by shifting the graph of $\boxed{ \ y = f(x) \ }$ upward v units.
$\boxed{ \ y = f(x) - v \ }$ by shifting the graph of $\boxed{ \ y = f(x) \ }$ downward v units.

That's the vertical shift, now the horizontal one. Given the graph of y = f(x) and h > 0, we obtain the graph of:

$\boxed{ \ y = f(x + h) \ }$ by shifting the graph of $\boxed{ \ y = f(x) \ }$ to the left h units.
$\boxed{ \ y = f(x - h) \ }$ by shifting the graph of $\boxed{ \ y = f(x) \ }$ to the right h units.

Therefore, the combination of vertical and horizontal shifts is as follows:

$\boxed{\boxed{ \ y = f(x \pm h) \pm v \ }}$

The plus or minus sign follows the direction of the shift, i.e., up-down or left-right.

- - - - - - - - - -

Let's solve the problem.

Initially, the graph of $y = \sqrt{x}$ is shifted 2 units up.

$\boxed{y = \sqrt{x} \rightarrow is \ shifted \ 2 \ units \ up \rightarrow \boxed{ \ y = \sqrt{x} + 2 \ }}$

Followed by shifting 5 units left.

$\boxed{y = \sqrt{x} + 2 \rightarrow is \ shifted \ 5 \ units \ left \rightarrow \boxed{ \ y = \sqrt{x + 5} + 2 \ }}$

Thus, the equation that represents the new graph is $\boxed{\boxed{ \ y = \sqrt{x + 5} + 2 \ }}$

The answer is A.

<h3>Learn more</h3>

Which phrase best describes the translation from the graph y = 2(x – 15)² + 3 to the graph of y = 2(x – 11)² + 3? brainly.com/question/1369568
The similar problem of shifting brainly.com/question/2488474
What transformations change the graph of (f)x to the graph of g(x)? brainly.com/question/2415963

Keywords: the graph of, y = √x, shifted 2 units up, 5 units left, which, the equation, represents, the new graph, horizontal, vertical, transformation geometry, translation

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3 years ago

Read 2 more answers

The owners of the Burger Emporium are looking for new supplier of onions for their famous hamburgers. It is important that the o

djverab [1.8K]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

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$\to P(9$

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As a result, onions through company A are chosen and they're more likely to be accepted.

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3 years ago

aliyah had some candy to give her four children. she first tooke ten pieces for herself and then evenly divided the rest among h

DIA [1.3K]

Let the original number be "x".
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4 years ago

Consider a medical study that is being performed to test the effect of smoking on lung cancer. Two groups of subjects are identi

Virty [35]

Answer:

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Step-by-step explanation:

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Another name for the response variable is the dependent variable. And it is the variable that we are testing for. This variable would respond to changes that are being made to the independent variable.

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3 years ago

Suppose that during a test drive of two cars, one car travels 186 miles in the same time that the second car travels 150 miles.

nevsk [136]

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Click here to see ALL problems on Exponential-and-logarithmic-functionsQuestion 726619: Skid mark analysis is one way to estimate the speed a car was traveling prior to an accident. The speed, s, that the vehicle was traveling in miles per hour can be approximated by the formula s=square root 30df, where d represents the length of the skid marks in fee and "f" represents the drag factor of the road. A vehicle that was involved in an accident on an asphalt road was traveling at a speed of 45 mph when it started skidding. If the drag factor for asphalt is 0.75 find the length of the skid marks made by the car. The skid marks made by the car were approximately___________ feet long. 
Answer by stanbon(75310) (Show Source):You can put this solution on YOUR website!
s=square root 30df, where d represents the length of the skid marks in feet and "f" represents the drag factor of the road. A vehicle that was involved in an accident on an asphalt road was traveling at a speed of 45 mph when it started skidding. If the drag factor for asphalt is 0.75 find the length of the skid marks made by the car.
S = sqrt(30df)
45 = sqrt(30*d*0.75)
----
45 = sqrt[(90/4)d]
-----
45 = (3/2)sqrt(10d)
30 = sqrt(10d)
10d = 900
d = 90 ft.
================

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3 years ago