$31,625
$2,590 x 12 months = 31,080
+ $545 = $31,625
Answer:
Option b.
Step-by-step explanation:
We can easily solve this problem by using a graphing calculator or plotting tool.
The function is
h(t) = cos (t +1)
Please, see attached picture below.
By looking at the picture, we can tell that the amplitude is equal to 1
The function has a period of T = 2π
We can see there is no vertical shift.
It has a phase shift of +1. (Which moves the graph to the left)
Answer:
Option b.
Answer:
120
Step-by-step explanation:
That's a guess, but it's the most logical one.
9514 1404 393
Answer:
- maximum: 15∛5 ≈ 25.6496392002
- minimum: 0
Step-by-step explanation:
The minimum will be found at the ends of the interval, where f(t) = 0.
The maximum is found in the middle of the interval, where f'(t) = 0.
![f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)](https://tex.z-dn.net/?f=f%28t%29%3D%5Csqrt%5B3%5D%7Bt%7D%2820-t%29%5C%5C%5C%5Cf%27%28t%29%3D%5Cdfrac%7B20-t%7D%7B3%5Csqrt%5B3%5D%7Bt%5E2%7D%7D-%5Csqrt%5B3%5D%7Bt%7D%3D%5Csqrt%5B3%5D%7Bt%7D%5Cleft%28%5Cdfrac%7B4%285-t%29%7D%7B3t%7D%5Cright%29)
This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...
f(5) = (∛5)(20-5) = 15∛5
The absolute maximum on the interval is 15∛5 at t=5.
Answer: y = 3x + 1
<u>Step-by-step explanation:</u>
The equation is in Slope-Intercept format: y = mx + b where
- m is the slope <em>(difference in y's over difference in x's)</em>
- b is the y-intercept <em>(value of y when x = 0)</em>

b = 1 <em>refer to the table that shows y = 1 when x = 0</em>
Now input m = 3 and b = 1 into the Slope-Intercept formula:
y = 3x + 1