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anyanavicka [17]
2 years ago
8

I NEED HELP ASAP ITS DUE SOON

Mathematics
1 answer:
almond37 [142]2 years ago
5 0

Answer:

Me is convuseld. . .

Step-by-step explanation:

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What are the key features of a graph of a quadratic equation with only complex solutions
dybincka [34]

Answer:

If  D< 0, the roots of the quadratic equation will b complex.

Step-by-step explanation:

Let ax^{2}  + bx + c =0 is the given quadratic equation.

So, if the Discriminant (D) = b^{2}  - 4ac  < 0, the the equation will have only complex solutions.

Complex roots are represented in the form of (x \pm iy)

1.  <u> x represents the X axis (real) co ordinate,</u>

    <u>y represents the Y axis (imaginary) coordinate</u>

<u />

<u />

2. Also, the graph of the with equation  D < 0  NEVER CROSSES the X - axis, as there are no real roots of the equation, only complex roots.

3. Here. roots are always identical but are opposite in signs. Such pair or roots with opposite sign are called CONJUGATE PAIRS.

4 0
3 years ago
The temperature is -2c. If the temperature rises by 15c what is the new temperature?
svetoff [14.1K]

Answer:

13c

Step-by-step explanation:

-2+15=13

13c

3 0
3 years ago
Read 2 more answers
Mrs.smith has 12 times as many markers as colored pencils.the total number of markers and colored pencils is 78.how many markers
cupoosta [38]
Divide 78 and 12. You get 6
6 0
3 years ago
6.
sweet-ann [11.9K]

Answer:

Step-by-step explanation:

<h3><em>The Answer is B, This is the answer beacuse R and S is true. There are some methonds you can do to help you solve any questions like these in the future. I hope this well help.</em></h3>
3 0
2 years ago
Read 2 more answers
A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit
m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0
3 years ago
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