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maks197457 [2]
3 years ago
9

What is sum of 12- 5 i and -3 +4

Mathematics
1 answer:
vesna_86 [32]3 years ago
8 0

Answer:

Sum- 13 - 5 i

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27x 5 + 9x 4 - 18x 3) 9x 2
notka56 [123]
In guessing it's 2,106.......
4 0
3 years ago
6. Darcy jogs 3 km in 20 min.
SOVA2 [1]

Answer:

a) 9 km

b) 18 km

c) She runs at a constant speed of 9 km/h

Step-by-step explanation:

7 0
3 years ago
Kinda putting this out here to everyone so you can learn. Don't just click on a person needing help then guess or just put gibbe
ElenaW [278]
Really true. just wanting points is not a reason to mess with someone else.
4 0
3 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
The data in the tables below were collected from first year students at a community college. The variable is “number of credit c
Colt1911 [192]

The probability that number of credit cards is 0 is 0.61

<h3>What is Probability ?</h3>

Probability is the likeliness of an event to happen ,

It has a range from 0 to 1 , where 0 indicates uncertainty while 1 indicates certainty

The data for the college students is given and it has been asked to determine P(0)

The total students are 200

and the students that have no credit card from the data is 122

Therefore

P(0) = 122/200 = 0.61

Therefore the probability that number of credit cards is 0 is 0.61

To know more about Probability

brainly.com/question/11234923

#SPJ1

8 0
2 years ago
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