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3 years ago

What is the volume of a cone with a height of 9.5 inches and a radius of 8 inches?

Mathematics

2 answers:

dem82 [27]3 years ago

7 0

Answer:

636.7in³

Step-by-step explanation:

V=πr2h

3=π·82·9.5

3≈636.69611in³

saul85 [17]3 years ago

7 0

Answer: 608/3

using my program, it simplifies up to 1/3 pi (608), and it wants you to write it as 608/3 in the answer box. Haven't seen a correct answer for my schooling program yet, hope this helps :)

edit: brainly censors my schooling program for some reason? but i use e*genuity (hope you can figure out what that one means :) )

Read more about perimeter at:

brainly.com/question/24571594

3 0

2 years ago

the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a

Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

$\frac{dm}{dt} = -\frac{m}{\tau}$ (Eq. 1)

Where:

$\frac{dm}{dt}$ - First derivative of mass in time, measured in miligrams per year.

$\tau$ - Time constant, measured in years.

$m$ - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

$\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt$

$\ln m = -\frac{1}{\tau} + C$

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ (Eq. 2)

Where:

$m_{o}$ - Initial mass of isotope, measured in miligrams.

$t$ - Time, measured in years.

And time is cleared within the equation:

$t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]$

Then, time constant can be found as a function of half-life:

$\tau = \frac{t_{1/2}}{\ln 2}$ (Eq. 3)

If we know that $t_{1/2} = 5730\,yr$ and $\frac{m(t)}{m_{o}} = 0.35$ , then:

$\tau = \frac{5730\,yr}{\ln 2}$

$\tau \approx 8266.643\,yr$

$t = -(8266.643\,yr)\cdot \ln 0.35$

$t \approx 8678.505\,yr$

The wood was cut approximately 8679 years ago.

5 0

3 years ago

carols bikes 1 kilometer east 4 kilometers north and then 5 kilometers east again. how far is caroll from her starting position

Volgvan

That'd be a total of 6 km east and 4 km north.

The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.

However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:

sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km

3 0

3 years ago

Read 2 more answers

You deposit $5000 in an account earning 2% interest compounded monthly. How much will you have in the account in 10 years?

sineoko [7]

Answer:

6000 dollars

Step-by-step explanation:

yadda yadda yadda that is the answer

4 0

3 years ago

Given the exponential equation, 3=18. Which of the equationsbelow will solve for x?

Zinaida [17]

Answer:

if you are evaluating this claim is false

7 0

3 years ago