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madam [21]
3 years ago
5

Emily knows that the area of a rectangle is 54x9y8 square yards and that it’s length 6x3y4 yards. If she divides the area by the

length to find the width, then which expression represents the width of her rectangle in yards?
A 9x3y2 B 48x6y4 C 9x6y4 D 60x12y12
Mathematics
1 answer:
Furkat [3]3 years ago
6 0

Answer:

Width of the rectangle is: \mathbf{Width= 9x^6 y^4}

Option C is correct.

Step-by-step explanation:

Area of rectangle = 54x^9y^8

Length of rectangle = 6x ^ 3y^4

We need to find width of rectangle.

The formula used is:

Area\:of\:rectangle=Length\times Width\\Width=\frac{Area\:of\:rectangle}{Length}

Putting values in the formula to find Width of rectangle

Width=\frac{Area\:of\:rectangle}{Length}\\Width=\frac{54x^9y^8}{6x^ 3y^4}

Using the exponent rule: \frac{a^m}{a^n}=a^{m-n}

and simplifying the terms we get

Width=\frac{54x^9y^8}{6x^3y^4}\\Width=9x^{9-3} \: y^{8-4}\\Width=9x^6 y^{4}

So, Width of the rectangle is: \mathbf{Width= 9x^6 y^4}

Option C is correct.

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Lostsunrise [7]

Answer:

1)12    2)a_{n}= a_{n+6}

Step-by-step explanation:

Problem 1:

a(5)=25    a(3)=13

a(5)-a(3)=25-13=12

mark brainliest

5 0
2 years ago
An economist uses the price of a gallon of milk as a measure of inflation. She finds that the average price is $3.82 per gallon
salantis [7]

Answer:

(a) The standard error of the mean in this experiment is $0.052.

(b) The probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c) The probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d) The likelihood that the sample mean is greater than $3.92 is 0.9726.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

n=40\\\mu=\$3.82\\\sigma=\$0.33

As <em>n</em> = 40 > 30, the distribution of sample mean is \bar X\sim N(3.82,\ 0.052^{2}).

(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{0.33}{\sqrt{40}}\\\\=0.052178\\\\\approx 0.052

Thus, the standard error of the mean in this experiment is $0.052.

(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

P(3.78

                               =P(-0.77

Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

\bar X-\mu_{\bar x}

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})

                    =P(Z

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

3 0
3 years ago
Pablo borrowed $900 from a credit union for 3years and was charged simple interest at a rate of 3%. What is the amount of intere
tensa zangetsu [6.8K]

Answer:81

Step-by-step explanation:

6 0
3 years ago
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Please help me ASAP I’ll mark Brainly
abruzzese [7]
Mark me Brainly answer 2/5
3 0
3 years ago
Pls help with math fast !!
Nutka1998 [239]

Answer:

1 would: You dont have to pay anything because 80% of 750 is $150 which you also have to deduct $150 so you dont pay anything.

2: 90% of $575 is $517 so 58 dollars would be deducted.

Hope this helps:)

7 0
3 years ago
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