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3 years ago

Find the value of x , if log₂ [log₅ (log₃x)] = 0

1 answer:

3 0

$\log_2 (\log_5( \log_3x)) = 0\\
D:x>0 \wedge \log_3x>0 \wedge \log_5(\log_3x)>0\\
D:x>0\wedge x>1 \wedge\log_3x>1\\
D:x>1 \wedge x>3\\
D:x>3\\
\log_5(\log_3x)=1\\
\log_3x=5\\
x=3^5\\
x=243$

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Harlamova29_29 [7]

Answer:

20 cm

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One month ruby wokred 6 more hours than isaac and svetlana worked 4 times as many as ruby they together worked 126 hours how man

jok3333 [9.3K]

R + R - 6 + 4R = 126
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3 years ago

Determine whether this pair of lines is parellel, perpendicular, or neither 6+2x=3y 3x+2y=9 Choose the correct answer below. A.

andriy [413]

Answer:

Option A. These two lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are equal

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

step 1

Convert the given equation A in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$6+2x=3y$ ----> equation A

Solve for y

That means----> isolate the variable y

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step 2

Convert the given equation B in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

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Solve for y

That means----> isolate the variable y

subtract 3x both sides

$2y=-3x+9$

Divide by 2 both sides

$y=-\frac{3}{2}x+4.6$

$m_B=-\frac{3}{2}$

step 3

Compare the slopes

$m_A=\frac{2}{3}$

$m_B=-\frac{3}{2}$

The slopes are opposite reciprocal (the product is equal to -1)

therefore

These two lines are perpendicular

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4 years ago

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Charra [1.4K]

The correct answer for this question is this one:

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