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Darina [25.2K]
3 years ago
13

Find the value of x , if log₂ [log₅ (log₃x)] = 0

Mathematics
1 answer:
Lina20 [59]3 years ago
3 0
\log_2 (\log_5( \log_3x)) = 0\\
D:x>0 \wedge \log_3x>0 \wedge \log_5(\log_3x)>0\\
D:x>0\wedge x>1 \wedge\log_3x>1\\
D:x>1 \wedge x>3\\
D:x>3\\
\log_5(\log_3x)=1\\
\log_3x=5\\
x=3^5\\
x=243
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