Question

Find the value of x , if log₂ [log₅ (log₃x)] = 0

Answer 1

$\log_2 (\log_5( \log_3x)) = 0\\ D:x>0 \wedge \log_3x>0 \wedge \log_5(\log_3x)>0\\ D:x>0\wedge x>1 \wedge\log_3x>1\\ D:x>1 \wedge x>3\\ D:x>3\\ \log_5(\log_3x)=1\\ \log_3x=5\\ x=3^5\\ x=243$