<h2>double, long, float, short, byte</h2>
Explanation:
The given data types are built-in types. According to java, the following holds right to justify the order.
Double:
- This occupies 64 bits
- It can hold decimal values
- Example: "1.23456e300d, -1.23456e-300d, 1e1d"
Float:
- It occupies 32 bits
- Holds decimal values
- Example: "1.23e100f, -1.23e-100f, .3f, 3.14F"
Long:
- It occupies 64 bits
- Example: "-2L, -1L, 0L, 1L, 2L"
Short:
- It occupies 16 bits
- Stores twos complement integer
Byte:
- Stores twos complement integer
Answer: B
Explanation:
if each color can be represented as 8 bits and you have 3 colors total that would mean you would need 24 bits to represent the entirety of the RGB spectrum. And each bit can either be on or off so you have two choices for each one. So the total amount of colors you can have for 8bit RGB would be 
which is 16,777,216.
Explanation:
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Answer: The answer is true
Answer:
def isAnagram(s1, s2):
list1=s1
list2=s2
sortedlist1 = sorted(list1)
sortedlist2 = sorted(list2)
if sortedlist1 == sortedlist2:
print(list1+ " and "+list2+ " are anagram")
else:
print(list1+ " and "+list2+ " are not anagram")
Explanation:
Here is a call to the function isAnagram():
list1 =input("Enter String1 ")
list1 =input("Enter String2 ")
isAnagram(list1,list2)
Attached is the run and output for this program
