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Nonamiya [84]
3 years ago
7

What celsius temperature, t2, is required to change the volume of the gas sample in part a (t1 = 43 ∘c , v1= 1.13×103 l ) to a v

olume of 2.26×103 l ? assume no change in pressure or the amount of gas in the balloon?
Chemistry
1 answer:
mamaluj [8]3 years ago
6 0
In this case, you are given the temperature and volume of the gas. To answer this question, you will need to use PV=nRT formula. Since the number of molecule and pressure is not changed then you can put 1 in both equations. The formula will become:

PV=nRT 
1 V= 1 T
V=T
T/V= 1

Dont forget that the celcius unit should be converted into kelvin. Then the calculation to find the temperature would be: 
T1/V1 = T2/V2
(43+273)/ 1.13x10^3 = T2/ 2.26 x 10^3
T2= (2.26 * 10^3) / (1.13 * 10^3) * (43+273)
T2= 2* 316= 632° K= 359°C
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Answer:

2

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The given reaction is formation of water. In this reaction oxygen and hydrogen react to form water and 486 kj/mol is also released.

The reaction in which heat is released is called exothermic reaction.

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The type of reactions in which energy is released are called exothermic reactions.

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C + O₂   →  CO₂

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it can be written as,

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C + H₂O   →  CO  + H₂

ΔH = +131 kj/mol

it can be written as,

C +  H₂O  + 131 kj/mol  →  CO  + H₂

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