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belka [17]
3 years ago
10

1) How many moles of atoms are in 3.00 g of 13C?2) Based on your answer in Part B, how many electrons are in this amount of 13C?

3) Based on your answer in Part B, how many neutrons are in this amount of 13C?
Chemistry
1 answer:
Alex787 [66]3 years ago
3 0

Answer:

1) 1.39 * 10²³ atoms

2) 8.43 * 10²³ electrons

3) 9.73 * 10²³ neutrons

Explanation:

1) 13 g of C-13 contains 6.02 *10²³ atoms

3.00 g of C-13 will contain 6.02 * 10²³ * (3/13) = 1.39 * 10²³ atoms

2) Each atom of C-13 contains 6 electrons

Therefore 3.00 g of C-13 will contain 6 * 1.39 * 10²³  electrons = 8.43 * 10²³ electrons

3) Each atom of C-13 contains 7 neutrons

Therefore, 3.00 g of C-13 will contain 7 * 1.39 * 10²³ neutrons = 9.73 * 10²³ neutrons

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\tt \dfrac{80.66}{12}\div \dfrac{7.39}{1}\div \dfrac{9.39}{14}\div \dfrac{2.68}{16}\\\\6.722\div 7.39\div 0.671\div 0.1675\rightarrow divide~by~smallest(0.1675)\\\\40\div 44\div 4\div 1

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