Parameterize S by the vector function
with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.
Compute the outward-pointing normal vector to S :
The integral of the field over S is then
For different function different results are shown below.
<h3>What is Function?</h3>
A function is a process or a relation that associates each element 'a' of a non-empty set A , at least to a single element 'b' of another non-empty set B.
We have been given a graph of piecewise function. Using that we have to select the function from given choices which is represented by graph.
g(x) = −2x, −2 < x < 0
Answer:
NO. Because g(x) = −2x has negative slope so that means it goes downward also there is no y-intercept in g(x) = −2x but the only graph that has y-intercept in given graph goes upward so that can't be answer.
g(x) = −2, x < −2
Answer:
YES. Because g(x) = −2 is a horizontal line which is only on the left side of x=-2. Graph of this part is present in given graph. So yes it is answer.
g(x) = x − 2, −2 < x < 1
Answer:
NO. Because g(x) = x−2 has y-intercept at y=-2 and slope 1 so that means graph of g(x)= x-2 must be going upward and crossing at y=-2 but there is no such graph. Hence this can't be answer.
g(x) = −2x + 6, x ≥ 1
Answer:
YES. Because g(x) = −2x+6 satisfies the graph which is going downward.
g(x) = x/2+ 1, –2 ≤ x < 1
Answer:
YES. Because g(x) = x/2+ 1 satisfies the graph which is going downward.
Learn more about function from:
brainly.com/question/12431044
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Apply the cosine double angle identity to get:
Cos 2PI/3
