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bearhunter [10]
3 years ago
10

You can buy 3 sandwiches for 4:$4.95 or 4 sandwiches for $6.72.Which is a better buy?

Mathematics
2 answers:
elixir [45]3 years ago
7 0
If you would like to know which one of the options is better to buy, you can calculate this using the following steps:

3 sandwiches ... $4.95
1 sandwich ... $x = ?
______________________
3 * x = 1 * 4.95       /3
x = 4.95 / 3 = $1.65


4 sandwiches ... $6.72
1 sandwich ... $y = ?
______________________
4 * y = 1 * 6.72     /4
y = 6.72 / 4 = $1.68

Result: You should buy sandwiches from the first option ($1.65 < $1.68 per unit).
Scrat [10]3 years ago
4 0
The unit rates for the first one id 1.65..The second one is 1.68.....So the first one is better..
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John walks m miles each week. Marie’s distance can be found by using the expression : 3m + ½
KiRa [710]

Answer:

21.5 Miles or 21 ½ Miles

Step-by-step explanation:

Plug in 7 as m to 3m + ½.

Then, I get 3(7) + ½.

That concludes to 21 + ½

Add the ".5" or "½" at the end

So, answer is you get is 21.5 of 21 ½

7 0
3 years ago
Lacy runs 5 1/4 km on Thursday. She runs 1 1/2 times as far on Saturday. How far does Lacy run on Saturday? Express your answer
natita [175]

Answer: 5 1/4 x 1 1/5 = 7 1/2 + 3/8 -> 7 7/8

The answer is 7 and 7/8

3 0
4 years ago
What is the probability that when a coin is flipped six times in a row, it lands heads up every time?
Elanso [62]
The possibility is 3 : 1/2 * 6/1 = 3/1
6 0
3 years ago
What is the radian measure of the smallest angle formed by the hands of a clock at 7 o'clock?
netineya [11]
See the picture attached to better understand the problem
we know that
a full circle is a 360 degrees
divided in 12 equals parts-------> 360/12-------> 30 degrees each part

<span>the smallest angle formed by the hands of a clock at 7 o'clock has 5 parts
so
5*30</span>°------> 150°

convert to radian
pi radians---------> 180°
 x ---------------> 150°
x=150*pi/180--------> x=0.83*pi radians

the answer is
0.83*pi radians  or 2.62 radians

5 0
3 years ago
Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.
finlep [7]

Answer:

a) v = \frac{[L]}{[T]} = LT^{-1}

b) a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}

c) \int v dt = s(t) = [L]=L

d) \int a dt = v(t) = [L][T]^{-1}=LT^{-1}

e) \frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

v = \frac{ds}{dt}

a= \frac{dv}{dt}

Part a

If we do the dimensional analysis for v we got:

v = \frac{[L]}{[T]} = LT^{-1}

Part b

For the acceleration we can use the result obtained from part a and we got:

a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}

Part c

From definition if we do the integral of the velocity respect to t we got the position:

\int v dt = s(t)

And the dimensional analysis for the position is:

\int v dt = s(t) = [L]=L

Part d

The integral for the acceleration respect to the time is the velocity:

\int a dt = v(t)

And the dimensional analysis for the position is:

\int a dt = v(t) = [L][T]^{-1}=LT^{-1}

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}

7 0
3 years ago
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