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3 years ago

HELP PLEASE I WILL MARK BRAINLIEST!!

Mathematics

2 answers:

Mamont248 [21]3 years ago

6 0

Answer:

5. (-2,-1) 6. (1,2) 7.(12,6)

Step-by-step explanation:

azamat3 years ago

3 0

Answer:

5. x=−2, y=−1

6. x=1, y=2

7. x=12 and y=6

Step-by-step explanation:

I hope this helped!

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Pleaseee helpp answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!

lord [1]

Answer:

8.9

Step-by-step explanation:

$d=\sqrt{(-7+3)^2+(-6-2)^2}$

$=\sqrt{16+64}\\=\sqrt{80}$

=8.9

7 0

3 years ago

What is the greatest common factor of the terms of the polynomial 12x^4 - 6x^3 + 9x^2

choli [55]

Answer:

$3x^{2}$ is the greatest common factor of the polynomial.

Step-by-step explanation:

Given:

The polynomial is $12x^{4} - 6x^{3} + 9x^{2}$

In order to determine the greatest common factor of all the terms, we find the greatest common factor of the coefficients separately and greatest common factor of the variables separately.

So, factors of 12 = 1, 2, 3, 4, 6, 12

Factors of 6 = 1, 2, 3, 6

Factors of 9 = 1, 3, 9

Therefore, the greatest common factor among 12, 6, and 9 is 3.

Now, factors of $x^{4}$ = $1, x, x^{2}, x^{3}, x^{4}$

Factors of $x^{3}$ = $1, x, x^{2}, x^{3}$

Factors of $x^{2}$ = $1, x, x^{2}$

Therefore, the greatest common factor among $x^{4}, x^{3},x^{2}$ is $x^{2}$ .

Hence, the greatest common factor of all the terms of the polynomial is $3x^{2}$

3 0

4 years ago

I'll give brainliest to whoever answers the question correctly!!!!

Leni [432]

Answer:

Is it statement 3? It looks like it doesn't belong.

6 0

3 years ago

Does anyone know 2 1⁄2 as a percent?

mojhsa [17]

Answer:

250%

Step-by-step explanation:

4 0

3 years ago

A sign next to a roller coaster at an amusement park says, “You must be at least 60 inches tall to ride.” Noah is happy to know

atroni [7]

Answer:

if Noah is 60 inches tall (5ft) and noah's friend is 2 inches shorter than he is 58inches tall, so no he won't be able to. but Noah could be 61 inches, but his friend is still to short.

7 0

3 years ago

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