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3 years ago

Admission to a theme park is $32 per adult and $20 per child. In order to pay the

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

Hello, your question is not mathematically solvable.

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Which of the following is not part of the job search preparation checklist

Flauer [41]

I think that a fact sheet is not a part of the job search preparation checklist. All the other options have some importance like the self assessment, follow-up plan and the resume. All this mentioned are needed and will help you on your job search preparation checklist.

D. Fact Sheet.

I hope this helps, Regards.

7 0

3 years ago

Read 2 more answers

A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as

Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that $p = 0.17$

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891$

0.3891 = 38.91% probability that only one is a second

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3 years ago

Do male and female servers work the same number of hours? A sample of 25 female servers worked an average of 26 hours per week,

Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

Given that

Group Group One Group Two

Mean 26.00 23.00

SD 2.00 4.00

SEM 0.40 1.21

N 25 11

where group I represents female servers and group II male servers.

We have to calculate confidence interval for 90% for difference in means

The mean of Group One minus Group Two equals 3.00

df = 34

standard error of difference = 0.993

t critical = 2.034 for 90% df 34

Hence confid. interval at 90%

=Mean diff ±2.034 * std error of diff

= (0.98, 5.02)

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3 years ago

What is the meaning of panchtantra???

DochEvi [55]

Answer:

<h2>✍ PANCHTANTRA :</h2>

⎆ The word “Panch.atantra” is a combination of the words Pancha – meaning five in Sanskrit, and Tantra – meaning weave. It's an ancient Indian inter-related collection of animal fables in verse and prose, in a frame story format.

⋆┈┈｡ﾟ❃ུ۪❀ུ۪❁ུ۪❃ུ۪❀ུ۪ﾟ｡┈┈⋆

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3 years ago

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In the circle below, DB = 22 cm, and m<DBC = 60°. Find BC. Ignore my handwriting.

Karo-lina-s [1.5K]

Answer:

$BC=11\ cm$