If a<=b<=c<=d<=e<=110 and the average of a,b,c,d,e is 100 what is the least possible value of a?. . options: 0 ,
1 answer:
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Answer:
72.14 units
Step-by-step explanation:
Let A(8,13), B(5,-18),C(-6,-6) and D(-2,-5)
Apply the distance formula as;
Finding the lengths of the segments
For AB
For BC
For CD
For DA
Finding the perimeter will be;
31.14+16.28+4.12+20.6=72.14 units
Answer: Choice C
The non-pencil part of the compass is placed at point G. The compass must be kept the same width that was used to form the arc shown. The idea is to draw another arc so that it starts above G (so its on the opposite side of point A) and traces out a similar path as the arc in the diagram.
Check out the attached image to see what I mean. The new second arc is shown in red.
The non-pencil part of the compass is placed at point G. The compass must be kept the same width that was used to form the arc shown. The idea is to draw another arc so that it starts above G (so its on the opposite side of point A) and traces out a similar path as the arc in the diagram.
Check out the attached image to see what I mean. The new second arc is shown in red.
No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.
Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have
and since the relation of order "<" is transitive, this implies