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zheka24 [161]
4 years ago
5

What is the initial value of the function represented by this graph?

Mathematics
2 answers:
MrRa [10]4 years ago
7 0
7 because it's the y-intercept
ruslelena [56]4 years ago
6 0

Answer:

Option D. 7

Step-by-step explanation:

The given function in the graph is a linear function, represented by the

f(x) = mx + c

Here m is the slope and c is the y intercept.

For any linear function initial value of the function is f(0) for x = 0

f(0)  = m×0 + c

      = c

For the given graph in the figure attached y- intercept is 7. Therefore, option D. 7 is the correct option.

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inna [77]

Answer:

1 and 3 is right and I’m pretty sure 2 is right also.

Step-by-step explanation:

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3 years ago
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10.) A meat shop sold 4 1/6 pounds of sausage and 4 times as much burger as sausages. How
meriva
16 2/3

you just need to multiply 4 1/6 by 4
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3 years ago
What is the first term in the sequence for which d = -2 and a7 = 3?
AnnZ [28]

Answer:

Final answer is c. 15

Step-by-step explanation:

We need to find about what is the first term in the sequence for which d = -2 and a7 = 3

We will use nth term formula of arithmetic sequence.

a_n=a+\left(n-1\right)d

we have been given a7 that means 7th term is 3

so plug n=7, d=-2 and a_n=3 into above formula

3=a+\left(7-1\right)(-2)

3=a+6(-2)

3=a-12

15=a

Hence final answer is c. 15

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4 years ago
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Find the angle measure of the missing angle for a triangle with angle measures of 37 degrees and 75 degrees.
alina1380 [7]
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8 0
3 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0
3 years ago
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