Since y=3x+15
sub 3x+15 for y in other equation
2x+3(3x+15)=1
2x+9x+45=1
minus 45
11x=-44
divide 11
x=-4
sub
y=3x+15
y=3(-4)+15
y=-12+15
y=3
(-4,3)
The most likely number of bags of peanuts she
sold is 20 bags of peanut at at $4 each
<h3>Equation</h3>
Kiyo:
94 = 10 + x
94 - 10 = x
84 = x
Aleja
94 = 14 + y
94 - 14 = y
80 = y
- Find the highest common factor of 84 and 80
80 = 1, 2, 4, 5, 8, 10, 16, 20, 40 and 80.
84 = 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42 and 84
- The highest common factor is 4
80 ÷ 4 = 20 bags of peanut
84 ÷ 4 = 21 bags of peanut
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Answer:
34 times 70
Step-by-step explanation:
2² - y - 5 = 0
Evaluate the power.
4 - y - 5 = 0
Calculate the sum or difference.
-1 - y = 0
Move constant to the right side and change its sign.
-y = 1
Change the signs on both sides of the equation.
y = -1
Answer:14
Step-by-step explanation: