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Leviafan [203]
4 years ago
14

I need work and know how to divide 1634÷ 1.900​

Mathematics
1 answer:
romanna [79]4 years ago
5 0

Answer: 860

Step-by-step explanation:

move the decimal from 1.900 to the back

1.900-----1900.

then take the imaginary decimal behind 1634. and move it to 3 places to left.            

then divide

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(3sqr3cis(pi/8))*(3sqr5cis(2pi/3))
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  9√15·cis(19π/24)

Step-by-step explanation:

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  = ((3√3)(3√5))·cis(π/8 +2π/3)

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4 years ago
Angle D is vertical angle to F the measure of is 53 what is the measure of
emmainna [20.7K]
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But again, would need the full question to be sure.
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4 years ago
In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead. Construct a 95% conden
S_A_V [24]

Answer:

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead.

This means that n = 42, \pi = \frac{26}{42} = 0.619

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

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The upper limit of this interval is:

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The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

4 0
3 years ago
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