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4 years ago

I need work and know how to divide 1634÷ 1.900

Mathematics

1 answer:

romanna [79]4 years ago

5 0

Answer: 860

Step-by-step explanation:

move the decimal from 1.900 to the back

1.900-----1900.

then take the imaginary decimal behind 1634. and move it to 3 places to left.

then divide

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(3sqr3cis(pi/8))*(3sqr5cis(2pi/3))

Volgvan

Answer:

9√15·cis(19π/24)

Step-by-step explanation:

The magnitudes multiply and the angles add:

= ((3√3)(3√5))·cis(π/8 +2π/3)

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4 years ago

Angle D is vertical angle to F the measure of is 53 what is the measure of

emmainna [20.7K]

Your question is missing some words and cannot be answered as asked.

However, it seems that the question is simply testing your knowledge of the term "vertical angles." Vertical angles are equal to each other. So if F and D are vertical angles, and one of them is 53°, then the other one is 53° as well.

But again, would need the full question to be sure.

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4 years ago

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead. Construct a 95% conden

S_A_V [24]

Answer:

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead.

This means that $n = 42, \pi = \frac{26}{42} = 0.619$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 - 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.472$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 + 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.766$

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

4 0

3 years ago

I need work and know how to divide 1634÷ 1.900​

I need work and know how to divide 1634÷ 1.900