1. C
2. 3, because I used a proportion table
Answer:
Step-by-step explanation:
for the first one is
Domain:
(−∞,∞),{x|x∈R}
Range:
(−7,∞),{y|y>−7}
Horizontal Asymptote:
y=−7
y-intercept(s):
(0,−6)
the second one is
y-intercept(s):
(0,8)
Horizontal Asymptote:
y=2
Domain:
(−∞,∞),{x|x∈R}
Range:
(2,∞),{y|y>2}
Answer: (3x + 11y)^2
Demonstration:
The polynomial is a perfect square trinomial, because:
1) √ [9x^2] = 3x
2) √121y^2] = 11y
3) 66xy = 2 *(3x)(11y)
Then it is factored as a square binomial, being the factored expression:
[ 3x + 11y]^2
Now you can verify working backwar, i.e expanding the parenthesis.
Remember that the expansion of a square binomial is:
- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2
=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.
Answer:
doesn't it give you the angles for each letter? If that is the case then it would be 33
Step-by-step explanation:
May I have brainliest please? :)
