Answer:
let the number of door tickets be x
so, eventually the number of advanced tickets will be. x-30
the total cost=2630.
(x-30)3+5x=2630
3x-90+5x=2630
8x-90=2630
8x=2630+90
8x/8=2720/8
x=340
x-30
340-30
310.
total tickets sold=310+340=650
Therefore, the total tickets bought was 650, 310 was advanced and 340 was door tickets
Answer: (-2,2)
Step-by-step explanation: -2 - -4 = -2 and 5 - 7 = 2 so I think (-2,2)
Let L be the low copper alloy and H be the high copper alloy.
We need 0.15L + 0.60H = 0.42 and L + H = 100
L=100 - H
Substituting this into the second equation for L, we get:
0.15(100-H) + 0.60H = 0.42(H+L)
15 - 0.15H + 0.60H = 0.42(H+100-H)
15 + 0.45H = 0.42(100)
0.45H = 42 - 15 = 27
H = 27/.45 = 60 lbs
Back substitution, L = 40 lbs.
Simply remember PEMDAS:
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
You perform these actions from left to right.
However in this case it is not possible for it to equal 60.