Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Hi
6 · (x-3) = 30
6(x) + 6(-3) = 30
6x - 18 = 30
6x = 30+18
6x = 48
x = 48/6
x = 8
Answer: the arithmetic sequence is
3, 10, 17, 24
Step-by-step explanation:
In an arithmetic sequence, the consecutive terms differ by a common difference. This means that the difference between the first term and the second term must equal the difference between the second term and the third term.
Considering the following sequences,
1) 4 - 1 = 3
9 - 4 = 5
There is no common difference and so, it is not an arithmetic sequence.
2) 10 - 3 = 7
17 - 10 = 7
The common difference is 7. So it is an arithmetic sequence.
3) 6 - - 5 = 11
10 - 6 = 4
There is no common difference and so, it is not an arithmetic sequence.
4) 2 - 1 = 1
4 - 2 = 2
There is no common difference and so, it is not an arithmetic sequence.
Answer:
can u explain
Step-by-step explanation:
